Use the given confidence interval limits to find the margin or error, express to four decimal places. 0.638 < u< 0.675
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Use the given confidence interval limits to find the margin or error, express to four decimal places. 0.638 < u< 0.675
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- Use the t-distribution to find a confidence interval for a mean μ given the relevant sample results. Give the best point estimate for μ, the margin of error, and the confidence interval. Assume the results come from a random sample from a population that is approximately normally distributed.A 90% confidence interval for μ using the sample results x¯=138.9, s=57.0, and n=50Round your answer for the point estimate to one decimal place, and your answers for the margin of error and the confidence interval to two decimal places.point estimate = margin of error = The 90% confidence interval isSelect the correct answer below: p-value >0.10 0.05< p-value <0.10 0.01< p-value <0.05 p-value <0.01Assume that a sample is used to estimate a population mean μμ. Find the 99.5% confidence interval for a sample of size 867 with a mean of 60.2 and a standard deviation of 21.9. Enter your answer as a tri-linear inequality accurate to 3 decimal places.
- Use the given information to find the number of degrees of fr, the critical values X2L and X2R and the confidence interval estimate of the standard deviation. It is reasonable to assume that a simple random sample has been selected from a population with a normal distribution. Nicotine in menthol cigarettes 95% confidence n= 20, s= 0.27 mg.Assume that a sample is used to estimate a population mean μμ. Find the 80% confidence interval for a sample of size 313 with a mean of 22.1 and a standard deviation of 19.4. Enter your answer as a tri-linear inequality accurate to one decimal place (because the sample statistics are reported accurate to one decimal place). < μμ <Assume that a sample is used to estimate a population mean u. Find the 99% confidence interval for a sample of size 376 with a mean of 16.8 and a standard deviation of 15.9. Enter your answer as a tri-linear inequality accurate to 3 decimal places.Express the confidence interval (0.025,0.079) in the form of p-EAn IQ test is designed so that the mean is 100 and the standard deviation is 10 for the population of normal adults. Find the sample size necessary to estimate the mean IQ score of statistics students such that it can be said with 99% confidence that the sample mean is within 4 IQ points of the true mean. Assume that σ=10 and determine the required sample size using technology. Then determine if this is a reasonable sample size for a real world calculation.Assume that a sample is used to estimate a population mean μμ. Find the 99% confidence interval for a sample of size 665 with a mean of 53.1 and a standard deviation of 8.5. Enter your answer as a tri-linear inequality accurate to 3 decimal places. ? < μ < ?Assume that a sample is used to estimate a population mean μμ. Find the 99.9% confidence interval for a sample of size 836 with a mean of 21.4 and a standard deviation of 15.6. Enter your answer as a tri-linear inequality accurate to one decimal place (because the sample statistics are reported accurate to one decimal place). < μμ <Researchers wants to determine if low-fat diets or low-carb diets are more effective for weight loss. Suppose 100 people were placed on a low-fat diet and at the end of 3 months the mean weight loss was 10.5 lbs witha standard deviation of 12.5 lbs. There were another 100 people placed on a low-carb diet and at the end of 3 months the mean weight loss was 16.5 lbs with a standard deviation of 10.2 lbs. Does mean weight lossdiffer between the two diets? What are the hypotheses??Recommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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