USE THE GIVEN BELOW.In a simple Rankine cycle, the steam throttled condition is 8 MPa and 480°C. The steam is then reheated to 2 MPa and 460 °C. If turbine exhaust is 60 °C, determine the following:a. Heat Added b. Turbine Work c. Heat Rejected d. Pump Work e. Net Work f.EfEfficiency 8 MPa and 480 °C (Table 3. Vapor) page 72h: = 3348.4 kJ/kgS1 = 6.6586 kJ/kg – KO 2 MPa (Table 3. Vapor; note: s1 = s2) page 46h2 = 2963.145 kJ/kg@ 2 MPa and 460 °C (Table 3. Vapor; note: s3 = Sa) page 46h3 = 3379.5 kJ/kgS3 = 7.3147 kl/kq – KSolving for haS3 = S4 = St + XSfg7.3147 kl/kg – K = 0.8312 kl/kg – K+ x (7.0784 kl/kg – K)x = 0.9159555832ha = h; + x(hja)hạ = 251.13 kl/kg + 0.9159555832 (2358.5 kJ/kg)ha = 2411.411243 kJ/kg@ 60°C (Table 1. Saturation Temperatures) page 3Ps= 0.019940 MPa19.94 kPa251.13 kJ/kg= 2358.5 kJ/kg= 0.8312 kJ/kg – K7.0784 kJ/kg -K= 0.0010172 m/kghsSigVVs

Turbine inlet=8MPa and 480CReheated =2MPa and 460CTurbine exhaust=60CTo-Find:-a. Heat addedb.…

Answered: USE THE GIVEN BELOW.In a simple Rankine…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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USE THE GIVEN BELOW.In a simple Rankine cycle, the steam throttled condition is 8 MPa and 480°C. The steam is then reheated to 2 MPa and 460 °C. If turbine exhaust is 60 °C, determine the following:

a. Heat Added

b. Turbine Work

c. Heat Rejected

d. Pump Work

e. Net Work

f.EfEfficiency

8 MPa and 480 °C (Table 3. Vapor) page 72
h: = 3348.4 kJ/kg
S1 = 6.6586 kJ/kg – K
O 2 MPa (Table 3. Vapor; note: s1 = s2) page 46
h2 = 2963.145 kJ/kg
@ 2 MPa and 460 °C (Table 3. Vapor; note: s3 = Sa) page 46
h3 = 3379.5 kJ/kg
S3 = 7.3147 kl/kq – K
Solving for ha
S3 = S4 = St + XSfg
7.3147 kl/kg – K = 0.8312 kl/kg – K+ x (7.0784 kl/kg – K)
x = 0.9159555832
ha = h; + x(hja)
hạ = 251.13 kl/kg + 0.9159555832 (2358.5 kJ/kg)
ha = 2411.411243 kJ/kg
@ 60°C (Table 1. Saturation Temperatures) page 3
Ps
= 0.019940 MPa
19.94 kPa
251.13 kJ/kg
= 2358.5 kJ/kg
= 0.8312 kJ/kg – K
7.0784 kJ/kg -K
= 0.0010172 m/kg
hs
Sig
V
Vs

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