Use the frequency distribution shown below to construct an expanded frequency distribution. High Temperatures (°F) Class 15-25 26-36 37-47 48-58 59-69 70-80 81-91 H Frequency, f 17 43 68 69 68 26 Complete the table below. High Temperatures (°F) (Round to the nearest hundredth as needed.) Relative Cumulative Class Frequency, f Midpoint frequency frequency 15-25 20 0.05 26-36 43 31 0.12 60 37-47 68

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### Constructing an Expanded Frequency Distribution

#### High Temperatures (°F)
The following table represents high temperatures and their frequencies:

| **Class** | **Frequency, f** |
|-----------|------------------|
| 15-25     | 17               |
| 26-36     | 43               |
| 37-47     | 68               |
| 48-58     | 69               |
| 59-69     | 74               |
| 70-80     | 68               |
| 81-91     | 26               |

#### Complete the Table Below

The following table needs to be completed by calculating midpoints, relative frequency, and cumulative frequency for the given classes of high temperatures. 

| **Class** | **Frequency, f** | **Midpoint** | **Relative Frequency** | **Cumulative Frequency** |
|-----------|------------------|--------------|------------------------|--------------------------|
| 15-25     | 17               | 20           | 0.05                   | 17                       |
| 26-36     | 43               | 31           | 0.12                   | 60                       |
| 37-47     | 68               |              |                        |                          |

**Instructions:**
1. To find the **midpoint** for each class:
   - Midpoint = (Lower class limit + Upper class limit) / 2
2. To find the **relative frequency**:
   - Relative Frequency = Frequency of the class / Total frequency (rounded to the nearest hundredth)
3. To find the **cumulative frequency**:
   - Cumulative Frequency = Sum of the frequencies for that class and all previous classes

Make sure to round the results to the nearest hundredth as needed.

**Example Calculation:**
- For the class 15-25:
  - Midpoint = (15 + 25) / 2 = 20
  - Total frequency from the first table = 17 + 43 + 68 + 69 + 74 + 68 + 26 = 365
  - Relative Frequency = 17 / 365 ≈ 0.05
  - Cumulative Frequency: 17 (as it’s the first class)

We have already calculated a few values and need to complete the rest similarly.
Transcribed Image Text:### Constructing an Expanded Frequency Distribution #### High Temperatures (°F) The following table represents high temperatures and their frequencies: | **Class** | **Frequency, f** | |-----------|------------------| | 15-25 | 17 | | 26-36 | 43 | | 37-47 | 68 | | 48-58 | 69 | | 59-69 | 74 | | 70-80 | 68 | | 81-91 | 26 | #### Complete the Table Below The following table needs to be completed by calculating midpoints, relative frequency, and cumulative frequency for the given classes of high temperatures. | **Class** | **Frequency, f** | **Midpoint** | **Relative Frequency** | **Cumulative Frequency** | |-----------|------------------|--------------|------------------------|--------------------------| | 15-25 | 17 | 20 | 0.05 | 17 | | 26-36 | 43 | 31 | 0.12 | 60 | | 37-47 | 68 | | | | **Instructions:** 1. To find the **midpoint** for each class: - Midpoint = (Lower class limit + Upper class limit) / 2 2. To find the **relative frequency**: - Relative Frequency = Frequency of the class / Total frequency (rounded to the nearest hundredth) 3. To find the **cumulative frequency**: - Cumulative Frequency = Sum of the frequencies for that class and all previous classes Make sure to round the results to the nearest hundredth as needed. **Example Calculation:** - For the class 15-25: - Midpoint = (15 + 25) / 2 = 20 - Total frequency from the first table = 17 + 43 + 68 + 69 + 74 + 68 + 26 = 365 - Relative Frequency = 17 / 365 ≈ 0.05 - Cumulative Frequency: 17 (as it’s the first class) We have already calculated a few values and need to complete the rest similarly.
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