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Use the formulas given below to express sech logarithms. sinh-lu= In (ut Vữ +1), uis 2 any real number tanh 1 1 1+u In 2 csch-¹ u = In 1 , |u| < 1 √1+u² |u| 20 sech 29 (Type an exact answer.) 20 29 2 cosh ¯¹u= In (u + √√u² −1), u≥1 sech ¹u = In - u #0 coth u= in terms of natural 1+√√1-u² u 1 u+1 2 In u-1' , |u| > 1 0

Use the formulas given below to express sech logarithms. sinh-lu= In (ut Vữ +1), uis 2 any real number tanh 1 1 1+u In 2 csch-¹ u = In 1 , |u| < 1 √1+u² |u| 20 sech 29 (Type an exact answer.) 20 29 2 cosh ¯¹u= In (u + √√u² −1), u≥1 sech ¹u = In - u #0 coth u= in terms of natural 1+√√1-u² u 1 u+1 2 In u-1' , |u| > 1 0

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Use the formulas given below to express sech logarithms. sinh-lu= In (ut Vữ +1), uis 2 any real number tanh 1 1 1+u In 2 csch-¹ u = In 1 , |u| < 1 √1+u² |u| 20 sech 29 (Type an exact answer.) 20 29 2 cosh ¯¹u= In (u + √√u² −1), u≥1 sech ¹u = In - u #0 coth in terms of natural u= In 1+√√1-u² u 1 u+1 '2'n u-1' , |u| > 1 0<u≤'
Transcribed Image Text:Use the formulas given below to express sech logarithms. sinh-lu= In (ut Vữ +1), uis 2 any real number tanh 1 1 1+u In 2 csch-¹ u = In 1 , |u| < 1 √1+u² |u| 20 sech 29 (Type an exact answer.) 20 29 2 cosh ¯¹u= In (u + √√u² −1), u≥1 sech ¹u = In - u #0 coth in terms of natural u= In 1+√√1-u² u 1 u+1 '2'n u-1' , |u| > 1 0<u≤'
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