Use the following table of data to calculate the average atomic mass of an unknown element, X: #protons #neutrons % abundance atomic mass (amu) 27.9769 92.2297% 4.6832% 28.9765 3.0872% 29.9738 14 14 14 14 15 16 mass number 28 29 30 Your prediction: A. The calculated value will be closest to 28. B. The calculated value will be closest to 29. C. The calculated value will be closest to 30.
Use the following table of data to calculate the average atomic mass of an unknown element, X: #protons #neutrons % abundance atomic mass (amu) 27.9769 92.2297% 4.6832% 28.9765 3.0872% 29.9738 14 14 14 14 15 16 mass number 28 29 30 Your prediction: A. The calculated value will be closest to 28. B. The calculated value will be closest to 29. C. The calculated value will be closest to 30.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
Transcribed Image Text:**Review & Preview: Calculating Average Atomic Mass**
To calculate the average atomic mass of an unknown element, X, refer to the data table below. The table lists isotopes of element X, characterized by their number of protons, number of neutrons, mass number, percentage abundance, and atomic mass (in amu).
| # protons | # neutrons | mass number | % abundance | atomic mass (amu) |
|-----------|------------|-------------|-------------|-------------------|
| 14 | 14 | 28 | 92.2297% | 27.9769 |
| 14 | 15 | 29 | 4.6832% | 28.9765 |
| 14 | 16 | 30 | 3.0872% | 29.9738 |
**Your Prediction:**
A. The calculated value will be closest to 28.
B. The calculated value will be closest to 29.
C. The calculated value will be closest to 30.
**Question:**
What evidence does the data contain to support your response?
---
To solve for the average atomic mass, consider the weighted contribution of each isotope based on its abundance.
Expert Solution
Step 1
Given data:
For isotope X-14 :
% Abundance = 92.2297 ÷ 100 = 0.922297
Atomic mass = 27.9769
For isotope X-15 :
% abundance = 4.6832 ÷ 100 = 0.046832
Atomic mass = 28.9765
For isotope X-16 :
% abundance = 3.0872 ÷100 = 0.030872
Atomic mass = 29.9738
Using the formula for average atomic mass :
Average atomic mass of X =
Sum of [Atomic mass × abundance ] of all isotopes
Step by step
Solved in 2 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY