Use the following starter code and complete the while loop: Starter code: j-0 sum12 - 0 while j < 100: ### Place your code below the ### Place your code above this print('') print('Total sum12 is:', sum12) Expected output: j: 0 sum12: 0 j: 12 sum12: 12 j: 24 sum12: 36 j: 36 sum12: 72 j: 48 sum12: 120 j: 60 sum12: 180 j: 72 sum12: 252 j: 84 sum12: 336 j: 96 sum12: 432 8 x 12+ 330 432 Total sum12 is: 432
Use the following starter code and complete the while loop: Starter code: j-0 sum12 - 0 while j < 100: ### Place your code below the ### Place your code above this print('') print('Total sum12 is:', sum12) Expected output: j: 0 sum12: 0 j: 12 sum12: 12 j: 24 sum12: 36 j: 36 sum12: 72 j: 48 sum12: 120 j: 60 sum12: 180 j: 72 sum12: 252 j: 84 sum12: 336 j: 96 sum12: 432 8 x 12+ 330 432 Total sum12 is: 432
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Transcribed Image Text:An experienced Python programmer in your company wants your assistance calculating the sum of
integer multipliers of 12 between 0 and up to 100 (including both ends). As an example:
while j < 100:
Use the following starter code and complete the while loop:
Starter code:
j-0
sum12 0
### Place your code below the
print (¹)
print('Total sum12 is:', sum12)
### Place your code above this ###
Expected output:
j: 0 sum12: 0
j: 12 sum12: 12
j: 24 sum12: 36
j: 36 sum12: 72
j: 48 sum12: 120
j: 60 sum12: 180
j: 72 sum12: 252
0 x 12+0=0
1x 12+0=12
2 × 12 + 12 = 36
3 x 12+36 72
j: 84 sum12: 336
j: 96 sum12: 432
⠀
6 x 12+180 252
7 x 12+252 = 336
8 x 12 +336 432
Total sum12 is: 432
Expert Solution

Requirement:
Write a Python program to compute the sum of integer multipliers of 12 between 0 and 100(including both ends). Also, display the final sum in the output.
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