Use the following sample to estimate a population mean μ.6565.247.185.463.968.357.169.636.865.86853.8Assuming the population is normally distributed, find the 99% confidence interval about thepopulation mean. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimalplaces.99% C.I. = A student was asked to find a 98% confidence interval for widget width using data from a randomsample of size n = 17. Which of the following is a correct interpretation of the interval 14.9 < µ<26.3?Check all that are correct.There is a 98% chance that the mean of a sample of 17 widgets will be between 14.9 and 26.3.The mean width of all widgets is between 14.9 and 26.3, 98% of the time. We know this is truebecause the mean of our sample is between 14.9 and 26.3.With 98% confidence, the mean width of all widgets is between 14.9 and 26.3.With 98% confidence, the mean width of a randomly selected widget will be between 14.9 and26.3.There is a 98% chance that the mean of the population is between 14.9 and 26.3.

Answered: Use the following sample to estimate a…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Use the following sample to estimate a population mean μ. 68 55.5 62.9 65 36.6 66.3 Assuming the population is normally distributed, find the 80% confidence interval about the population mean. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places.80% C.I. =
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A laboratory tested 85 chicken eggs and found that the mean amount of cholesterol was 191 milligrams. Assume that o = 16.2 milligrams. Construct a 95% confidence interval for the true mean cholesterol content, µ, of all such eggs. Round to one decimal place. O A. 186.9 to 195.1 milligrams B. 186.5 to 195.5 milligrams C. 188.1 to 193.9 milligrams D. 187.6 to 194.4 milligrams
Use the following sample to estimate a population mean u. -0.4 41.3 -2.6 7.6 33.5 22.7 33.1 47.1 13.8 -8.6 36.8 Assuming the population is normally distributed, find the 90% confidence interval about the population mean. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places. 90% C.I. =
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Use the given sample data to construct the indicated confidence interval for the population mean. The football coach randomly selected ten players and timed how long each player took to perform a certain drill. The times (in minutes) were: 12.7 14.6 11.7 12.6 11.5 11.2 7.2 10.3 7.2 9.1 Determine a 95% confidence interval for the mean time for all players. O A. (9.00, 12.62) O B. (9.57, 12.05) O C. (9.09, 12.53 ) O D. (9.29, 12.30 ) O E. (9.50, 12.12)
K In a random sample of eleven people, the mean driving distance to work was 22.3 miles and the standard deviation was 4.9 miles. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean u. Interpret the results. Identify the margin of error. (Round to one decimal place as needed.) Construct a 95% confidence interval for the population mean. (Round to one decimal place as needed.) Interpret the results. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or a decimal. Do not round.) OA. It can be said that % of the population has a driving distance to work (in miles) that is between the interval's endpoints. O B. % of all random samples of eleven people from the population will have a mean driving distance to work (in miles) that is between the interval's endpoints. OC. With % confidence, it can be said that most driving distances…

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