Use the following sample to estimate a population mean μ. 65 65.2 47.1 85.4 63.9 68.3 57.1 69.6 36.8 65.8 68 53.8 Assuming the population is normally distributed, find the 99% confidence interval about the population mean. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places. 99% C.I. =
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- Please answer within 30min thanks. n= 15 for the 96% confidence interval for the mean.You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 54 38.9 43.1 53.1 74.6 48.4 59.5 71.6 95.8 Find the 95% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population.95% C.I. =Use the following sample to estimate a population mean μ. 68 55.5 62.9 65 36.6 66.3 Assuming the population is normally distributed, find the 80% confidence interval about the population mean. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places.80% C.I. =
- 2.5 A confidence interval estimate is constructed around a. the degree of confidence b. the population parameter C. the population mean d. the point estimate 2.6 The z value that is used to construct a 95% confidence interval is: a. 2,58 b. 1.65 C. 1.96 d. 1.28 2.7 Which of the following is NOT a property of the student'st distribution? a. It's exact shape (i.e., spread) is characterized by the degrees of freedom b. It is symmetric c. All of the above are properties of the t distribution d. As the sample size grows, it gradually approaches the normal distributionYou must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 45.5 52.8 69.7 66 59.1 67 74.6 43.7 61.1 27.4 64.7 Find the 95% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 95% C.I. =A variable of a population has a normal distribution. Suppose that you want to find a confidence interval for the population mean. a. If you know the population standard deviation, which procedure would you use?b. If you do not know the population standard deviation, which procedure would you use?
- Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.To build a 95% CI for the mean of a population, you take a random sample and find these values: 18.4 19.8 17 18.6 23 21.7 18.9 14.3 17.6 21.2 21.4 23.4 20 20.7 15.2 21.9 21 What is the CI? Enter like this: (min,max) Be sure to use the parentheses or you will be marked wrong. Keep at least 3 decimals in all intermediate steps, and round your answer to two decimals. Submit QuestionA laboratory tested 85 chicken eggs and found that the mean amount of cholesterol was 191 milligrams. Assume that o = 16.2 milligrams. Construct a 95% confidence interval for the true mean cholesterol content, µ, of all such eggs. Round to one decimal place. O A. 186.9 to 195.1 milligrams B. 186.5 to 195.5 milligrams C. 188.1 to 193.9 milligrams D. 187.6 to 194.4 milligrams
- Use the following sample to estimate a population mean u. -0.4 41.3 -2.6 7.6 33.5 22.7 33.1 47.1 13.8 -8.6 36.8 Assuming the population is normally distributed, find the 90% confidence interval about the population mean. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places. 90% C.I. =Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96Find the 99% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place).99% C.I. =