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Use the following procedure for the recurrence relation an=2nan-1 with the initial condition ag = 3. an=2nan-1 = 2n(2(n-1)an - 2) = 2²(n(n-1))an - 2 = 2²(n(n-1))(2(n - 2)an - 3) = 2³ (n(n-1)(n-2))an - 3 =... continuing in the same manner = 2^n(n-1)(n-2)(n-3)(n-(n-1))an-n = 2^n(n – 1)(n – 2)(n – 3) - - - 1 - ao Multiple Choice O 3-2 (n+1)! 3-2 n! 20 n! 3-2 (n-1)!

Use the following procedure for the recurrence relation an=2nan-1 with the initial condition ag = 3. an=2nan-1 = 2n(2(n-1)an - 2) = 2²(n(n-1))an - 2 = 2²(n(n-1))(2(n - 2)an - 3) = 2³ (n(n-1)(n-2))an - 3 =... continuing in the same manner = 2^n(n-1)(n-2)(n-3)(n-(n-1))an-n = 2^n(n – 1)(n – 2)(n – 3) - - - 1 - ao Multiple Choice O 3-2 (n+1)! 3-2 n! 20 n! 3-2 (n-1)!

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.4: Complex And Rational Zeros Of Polynomials
Problem 46E
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Use the following procedure for the recurrence relation an= 2nan-1 with the initial condition ag = 3. an=2nan-1 = 2n(2(n-1)an - 2) = 2² (n(n-1))an - 2 = 2²(n(n-1))(2(n − 2)an - 3) - = 2³ (n(n-1)(n − 2))an - 3 = ... continuing in the same manner = 2^n(n-1)(n-2)(n-3)(n-(n-1))an-n = 2^n(n – 1)(n – 2)(n – 3) - - - 1 - ao || Multiple Choice 3-2 (n+1)! 3-2 n! 27 n! 3-2" (n-1)!
Transcribed Image Text:Use the following procedure for the recurrence relation an= 2nan-1 with the initial condition ag = 3. an=2nan-1 = 2n(2(n-1)an - 2) = 2² (n(n-1))an - 2 = 2²(n(n-1))(2(n − 2)an - 3) - = 2³ (n(n-1)(n − 2))an - 3 = ... continuing in the same manner = 2^n(n-1)(n-2)(n-3)(n-(n-1))an-n = 2^n(n – 1)(n – 2)(n – 3) - - - 1 - ao || Multiple Choice 3-2 (n+1)! 3-2 n! 27 n! 3-2" (n-1)!
The recurrence relation an = an-1+3 with the initial condition ao = 1 Multiple Choice O The solution for the recurrence relation is an = 3+ an-1=3+3+ an-2=2.3+ an-2 =3.3+an-3 == n.3+ an-n= n. 3+ ao = 3n+1 O The solution for the recurrence relation is an = 3 + an-1= 32+ an- 2 = 33+ an-3 = . = 3n+ O an-n=37+ + a0 = 37+1 -= O The solution for the recurrence relation is an = 3 + an-1=3+ an-2=3+an-2 = 3+ an-3 = = 3+ an-n=3+ ao = 3 + 1=4 The solution for the recurrence relation is an = 3+ an-1-3-3+an-2= an-2= an-3=an-n= a0 = 1
Transcribed Image Text:The recurrence relation an = an-1+3 with the initial condition ao = 1 Multiple Choice O The solution for the recurrence relation is an = 3+ an-1=3+3+ an-2=2.3+ an-2 =3.3+an-3 == n.3+ an-n= n. 3+ ao = 3n+1 O The solution for the recurrence relation is an = 3 + an-1= 32+ an- 2 = 33+ an-3 = . = 3n+ O an-n=37+ + a0 = 37+1 -= O The solution for the recurrence relation is an = 3 + an-1=3+ an-2=3+an-2 = 3+ an-3 = = 3+ an-n=3+ ao = 3 + 1=4 The solution for the recurrence relation is an = 3+ an-1-3-3+an-2= an-2= an-3=an-n= a0 = 1
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