Use the following information to answer the next question NaCI(s) + ½ H20(1)HCI(g) + % Na,O(s) AH = +253.65 kJ 2 NaNO2(s) NO(g) + NO2(g) + Na,0(s) AH = +427.14 kJ NO(g) + NO2(g)→N20(g) + O2(g) N20(g) + % O2(g) + % H2O(1)HNO2(1) AH = -17.18 kJ AH = -42.68 kJ 1 %3D 4. Using the above information, calculate the AH for the following reaction: HCI(g) + NaNO2(s) HNO2(1) + NaCI(s) AH = ? O-157.2 kJ O +78.6 kJ O+157.2 kJ -78.6 kJ
Use the following information to answer the next question NaCI(s) + ½ H20(1)HCI(g) + % Na,O(s) AH = +253.65 kJ 2 NaNO2(s) NO(g) + NO2(g) + Na,0(s) AH = +427.14 kJ NO(g) + NO2(g)→N20(g) + O2(g) N20(g) + % O2(g) + % H2O(1)HNO2(1) AH = -17.18 kJ AH = -42.68 kJ 1 %3D 4. Using the above information, calculate the AH for the following reaction: HCI(g) + NaNO2(s) HNO2(1) + NaCI(s) AH = ? O-157.2 kJ O +78.6 kJ O+157.2 kJ -78.6 kJ
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Use the following information to answer the next question
NaCI(s) + ½ H2O(1) HCI(g) + % Na,O(s) AH = +253.65 kJ
2 NaNO,(s) - NO(g) + NO2(g) + Na,0(s) AH +427.14 kJ
NO(g) + NO2(g)N20(g) + O2(g)
½N2O(g) + ½ O2(g) + H20(1) HNO2(1) AH = -17.18 kJ
AH = -42.68 kJ
4.
Using the above information, calculate the AH for the following reaction:
HCI(g) + NaNO2(s) HNO2(1) + NaCI(s) AH = ?
O-157.2 kJ
+78.6 kJ
O+157.2 kJ
O-78.6 kJ
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Use the following information to answer the next question
Hydrazine, N2H4(1), has been used as a rocket fuel. The reaction representing the
combustion of hydrazine is shown below.
N2H4(1) + 302(g) -→ 2 NO2(g) + 2H20(g) + 400kJ
Numeric Response
4.
The mass of hydrazine necessary to release 150 MJ of energy is
kg
(Record your three-digit answer in the numerical-response section below.)
D000
Your answer:
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