Use the following empirical expressions for the molar heat capacities of solid, liquid andgaseous forms of water(i)?̅?[H2O(s)]?= −0.2985 + (2.896 × 10−2 K−1)? − (8.6714 × 10−5 K−2)?2 +(1.703 × 10−7 K−3)?3 10 K ≤ T ≤ 273.15 K(ii)?̅?[H2O(l)]?= 22.447 − (0.11639 K−1)? + (3.3312 × 10−4 K−2)?2 −(3.1314 × 10−7 K−3)?3 273.15 K ≤ T ≤ 373.15 K(iii)?̅?[H2O(g)]?= 3.652 + (1.156 × 10−3K−1)? − (1.424 × 10−7 K−2)?2373.15 K ≤ T ≤ 1000 Kto plot the standard molar entropy of water from 0 K to 1000 K. Use the following empirical expressions for the molar heat capacities of solid, liquid andgaseous forms of waterČp[H,0(s)](i)= -0.2985 + (2.896 x 10-2 K-1)T – (8.6714 x 10-5 K-2)T² +R(1.703 x 10-7 K-3)T310 KSTS 273.15 K(ii)Čp[H20(1)]= 22.447 – (0.11639 K-1)T + (3.3312 x 10-4 K-2)T2 –R(3.1314 x 10-7 K-3)T3273.15 KSTS 373.15 K(ii)Čp[H20(g)]= 3.652 + (1.156 x 10-3K-1)T – (1.424 x 10-7 K-2)T²373.15 KSTS 1000 Kto plot the standard molar entropy of water from OK to 1000 K.

Given, molar heat capacities are C⏜pR = -0.2985 +2.896×10-2T-8.6714×10-5T2 +1.703×10-7T3; 10…

Answered: Use the following empirical expressions…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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Question

Use the following empirical expressions for the molar heat capacities of solid, liquid and
gaseous forms of water
(i)
?̅?[H2O(s)]
?
= −0.2985 + (2.896 × 10−2 K
−1
)? − (8.6714 × 10−5 K
−2
)?
2 +
(1.703 × 10−7 K
−3
)?
3 10 K ≤ T ≤ 273.15 K
(ii)
?̅?[H2O(l)]
?
= 22.447 − (0.11639 K
−1
)? + (3.3312 × 10−4 K
−2
)?
2 −
(3.1314 × 10−7 K
−3
)?
3 273.15 K ≤ T ≤ 373.15 K
(iii)
?̅?[H2O(g)]
?
= 3.652 + (1.156 × 10−3K
−1
)? − (1.424 × 10−7 K
−2
)?
2
373.15 K ≤ T ≤ 1000 K
to plot the standard molar entropy of water from 0 K to 1000 K.

Use the following empirical expressions for the molar heat capacities of solid, liquid and
gaseous forms of water
Čp[H,0(s)]
(i)
= -0.2985 + (2.896 x 10-2 K-1)T – (8.6714 x 10-5 K-2)T² +
R
(1.703 x 10-7 K-3)T3
10 KSTS 273.15 K
(ii)
Čp[H20(1)]
= 22.447 – (0.11639 K-1)T + (3.3312 x 10-4 K-2)T2 –
R
(3.1314 x 10-7 K-3)T3
273.15 KSTS 373.15 K
(ii)
Čp[H20(g)]
= 3.652 + (1.156 x 10-3K-1)T – (1.424 x 10-7 K-2)T²
373.15 KSTS 1000 K
to plot the standard molar entropy of water from OK to 1000 K.

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