Use the following data to estimate AH°f for magnesium fluoride. Mg(s) + F₂(g) → MgF₂(s) Lattice energy = - 2913 kJ/mol == First ionization energy of Mg =735 kJ/mol Second ionization energy of Mg= 1445 kJ/mol Electron affinity of F= -328 kJ/mol Bond energy of F₂ =154 kJ/mol Enthalpy of sublimation for Mg = 150. kJ/mol Select one or more: 167 kJ/mol -411 kJ/mol -1085 kJ/mol -292 kJ

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Use the following data to estimate AH°f for
magnesium fluoride.
Mg(s) + F₂(g) →→ MgF₂(s)
Lattice energy = 2913 kJ/mol
First ionization energy of Mg =735 kJ/mol
Second ionization energy of Mg= 1445
kJ/mol
Electron affinity of F= -328 kJ/mol
Bond energy of F₂ =154 kJ/mol
Enthalpy of sublimation for Mg =150.
kJ/mol
Select one or more:
167 kJ/mol
-411 kJ/mol
-1085 kJ/mol
-292 kJ
Transcribed Image Text:Use the following data to estimate AH°f for magnesium fluoride. Mg(s) + F₂(g) →→ MgF₂(s) Lattice energy = 2913 kJ/mol First ionization energy of Mg =735 kJ/mol Second ionization energy of Mg= 1445 kJ/mol Electron affinity of F= -328 kJ/mol Bond energy of F₂ =154 kJ/mol Enthalpy of sublimation for Mg =150. kJ/mol Select one or more: 167 kJ/mol -411 kJ/mol -1085 kJ/mol -292 kJ
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