Homework Help is Here – Start Your Trial Now!
Science
Physics
Use the following constants if necessary. Coulomb constant, k=8.987×109N•m2/C2. Vacuum permitivity, €o=8.854×10-12F/m. Magnetic Permeability of vacuum, uo=12.566370614356×10-7H/m. Magnitude of the Charge of one electron, e=-1.60217662×10-19C. Mass of one electron, me=9.10938356×10-31kg. Unless specified otherwise, each symbol carries their usual meaning. For example, µC means microcoulomb. The figure (Fig. 1) shows a long cylindrical capacitor consists of a solid conducting core with radius ri=3mm and outer hollow conducting tube with an inner radius of r2=33mm. The length of the capacitor is L=27cm. Figure 2 is the cross sectional view of the system. This system of rod and shell is connected to a voltage source of emf E=6.4volts. There is no dielectric material present in the system as of now. Fig.2 A) Calculate the capacitance of this capacitor. B) Say the inner rod is positively charged. Given this, calculate the charge density of the outer surface. And show how the electric field lines are oriented in this system. Hint: you can use the cross section for this (Fig. 2). What is charge density of the outer surface? C) we disconnect the battery from the capacitor and then we insert a dielectric material between the rod and shell, replacing air completely. The dielectric constant of the material is K as before. Calculate the potential differece between between the rod and shell at this point.

Use the following constants if necessary. Coulomb constant, k=8.987×109N•m2/C2. Vacuum permitivity, €o=8.854×10-12F/m. Magnetic Permeability of vacuum, uo=12.566370614356×10-7H/m. Magnitude of the Charge of one electron, e=-1.60217662×10-19C. Mass of one electron, me=9.10938356×10-31kg. Unless specified otherwise, each symbol carries their usual meaning. For example, µC means microcoulomb. The figure (Fig. 1) shows a long cylindrical capacitor consists of a solid conducting core with radius ri=3mm and outer hollow conducting tube with an inner radius of r2=33mm. The length of the capacitor is L=27cm. Figure 2 is the cross sectional view of the system. This system of rod and shell is connected to a voltage source of emf E=6.4volts. There is no dielectric material present in the system as of now. Fig.2 A) Calculate the capacitance of this capacitor. B) Say the inner rod is positively charged. Given this, calculate the charge density of the outer surface. And show how the electric field lines are oriented in this system. Hint: you can use the cross section for this (Fig. 2). What is charge density of the outer surface? C) we disconnect the battery from the capacitor and then we insert a dielectric material between the rod and shell, replacing air completely. The dielectric constant of the material is K as before. Calculate the potential differece between between the rod and shell at this point.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
See similar textbooks
icon
Related questions
Question
Use the following constants if necessary. Coulomb constant, k=8.987×109N•M2/C2. Vacuum permitivity, €0=8.854x10-12F/m. Magnetic Permeability of vacuum, µo=12.566370614356×10-7H/m. Magnitude of the Charge of one electron, e=-1.60217662x10-19C. Mass of one electron, me=9.10938356x10-31kg. Unless specified otherwise, each symbol carries their usual meaning. For example, µC means microcoulomb. The figure (Fig. 1) shows a long cylindrical capacitor consists of a solid conducting core with radius ri=3mm and outer hollow conducting tube with an inner radius of r2=33mm. The length of the capacitor is L=27cm. Figure 2 is the cross sectional view of the system. This system of rod and shell is connected to a voltage source of emf E=6.4volts. There is no dielectric material present in the system as of now. Fg-2 A) Calculate the capacitance of this capacitor. B) Say the inner rod is positively charged. Given this, calculate the charge density of the outer surface. And show how the electric field lines are oriented in this system. Hint: you can use the cross section for this (Fig. 2). What is charge density of the outer surface? C) we disconnect the battery from the capacitor and then we insert a dielectric material between the rod and shell, replacing air completely. The dielectric constant of the material is K as before. Calculate the potential differece between between the rod and shell at this point.
Transcribed Image Text:Use the following constants if necessary. Coulomb constant, k=8.987×109N•M2/C2. Vacuum permitivity, €0=8.854x10-12F/m. Magnetic Permeability of vacuum, µo=12.566370614356×10-7H/m. Magnitude of the Charge of one electron, e=-1.60217662x10-19C. Mass of one electron, me=9.10938356x10-31kg. Unless specified otherwise, each symbol carries their usual meaning. For example, µC means microcoulomb. The figure (Fig. 1) shows a long cylindrical capacitor consists of a solid conducting core with radius ri=3mm and outer hollow conducting tube with an inner radius of r2=33mm. The length of the capacitor is L=27cm. Figure 2 is the cross sectional view of the system. This system of rod and shell is connected to a voltage source of emf E=6.4volts. There is no dielectric material present in the system as of now. Fg-2 A) Calculate the capacitance of this capacitor. B) Say the inner rod is positively charged. Given this, calculate the charge density of the outer surface. And show how the electric field lines are oriented in this system. Hint: you can use the cross section for this (Fig. 2). What is charge density of the outer surface? C) we disconnect the battery from the capacitor and then we insert a dielectric material between the rod and shell, replacing air completely. The dielectric constant of the material is K as before. Calculate the potential differece between between the rod and shell at this point.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Magnetic field
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON
SEE MORE TEXTBOOKS