Use the following chemical equation C6H12 +9 02: 6 CO2 + 6 H20 ----> (OR C6H12 + 9 02 right arrow 6 CO2 + 6 H20) How many grams of O2 gas are required to react with 101.0 grams of C6H12? The molecular weight of water is 18.02 g/mol The molecular weight of CO2 is 44.01 g/mol The molecular weight of O02 is 32.00 g/mol The molecular weight of C6H12 is 84.18 g/mol 1 mole of a gas at STP is 22.414 L Do not type units with your answer Vour Ancwor

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Use the following chemical equation
C6H12 + 9 02 ----> 6 CO2 + 6 H20
(OR C6H12 + 9 O2 right arrow 6 CO2 + 6 H20)
How many grams of O2 gas are required to react with 101.0 grams of C6H12?
The molecular weight of water is 18.02 g/mol
The molecular weight of CO2 is 44.01 g/mol
The molecular weight of 02 is 32.00 g/mol
The molecular weight of C6H12 is 84.18 g/mol
1 mole of a gas at STP is 22.414 L
Do not type units with your answer
Your Answer:
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Transcribed Image Text:Use the following chemical equation C6H12 + 9 02 ----> 6 CO2 + 6 H20 (OR C6H12 + 9 O2 right arrow 6 CO2 + 6 H20) How many grams of O2 gas are required to react with 101.0 grams of C6H12? The molecular weight of water is 18.02 g/mol The molecular weight of CO2 is 44.01 g/mol The molecular weight of 02 is 32.00 g/mol The molecular weight of C6H12 is 84.18 g/mol 1 mole of a gas at STP is 22.414 L Do not type units with your answer Your Answer: Answer
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