Use the following building blocks in the right column to assemble a direct proof that the product of two odd numbers is odd. Not all blocks belong in the proof.

Database System Concepts
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Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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Use the following building blocks in the right column to assemble a direct proof that the product of two odd numbers is odd.

Not all blocks belong in the proof.

 

Use the following building blocks in the right column to assemble a direct proof that the product of two odd numbers is
odd.
Not all blocks belong in the proof.
Suppose that n and m are odd numbers.
By multiplying these equations,
we obtain nm (2k + 1)(2q + 1).
By definition of an odd integer, that means that nm is odd.
Then n = 2k + 1 and m = 2k + 1 for some integer k.
Suppose that the product of two odd numbers is odd.
Distributing, we get nm=2(2kq +k+q) + 1.
Then n = 2k + 1 for some integer k and
m = 2q + 1 for some integer q.
Suppose that nm is odd.
Transcribed Image Text:Use the following building blocks in the right column to assemble a direct proof that the product of two odd numbers is odd. Not all blocks belong in the proof. Suppose that n and m are odd numbers. By multiplying these equations, we obtain nm (2k + 1)(2q + 1). By definition of an odd integer, that means that nm is odd. Then n = 2k + 1 and m = 2k + 1 for some integer k. Suppose that the product of two odd numbers is odd. Distributing, we get nm=2(2kq +k+q) + 1. Then n = 2k + 1 for some integer k and m = 2q + 1 for some integer q. Suppose that nm is odd.
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