Use the figure below to find all angles between 0 and 2n satisfying the given condition. (Enter your answers as a comma- separated list.) csc(0) = 2 1 V3 (0, 1) 1 V3 2 2 1 1 2 2. 1 45° = A/4 30° = x/6 150° = 5 x/6 2 180 ° = (-1, 0) 360 ° = 2 7 (1, 0) 330° = 11 x/6 210° = 7x/6 V3 V3 2. 225° = 5 a/4 2 1 1 1 1 V3 V3 2 2 (0, -1) 2 2 7/u = . 06 60° = x/3 120° = 2 x/3 315° = 7 x/4 300° = 5 x/3 135° = 3 n/4 270° = 3 x/2 240 ° =4 x/3

Use the figure below to find all angles between 0 and 2n satisfying the given condition. (Enter your answers as a comma- separated list.) csc(0) = 2 1 V3 (0, 1) 1 V3 2 2 1 1 2 2. 1 45° = A/4 30° = x/6 150° = 5 x/6 2 180 ° = (-1, 0) 360 ° = 2 7 (1, 0) 330° = 11 x/6 210° = 7x/6 V3 V3 2. 225° = 5 a/4 2 1 1 1 1 V3 V3 2 2 (0, -1) 2 2 7/u = . 06 60° = x/3 120° = 2 x/3 315° = 7 x/4 300° = 5 x/3 135° = 3 n/4 270° = 3 x/2 240 ° =4 x/3

Trigonometry (11th Edition)

11th Edition

ISBN:9780134217437

Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Chapter1: Trigonometric Functions

Section: Chapter Questions

Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.

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Question

Use the figure below to find all angles between 0 and 2n satisfying the given condition. (Enter your answers as a comma-
separated list.)
csc(0) = 2
1 V3
(0, 1)
1 V3
2
2
1
1
2
2.
1
45° = A/4
30° = x/6
150° = 5 x/6
2
180 ° =
(-1, 0)
360 ° = 2 7
(1, 0)
330° = 11 x/6
210° = 7x/6
V3
V3
2.
225° = 5 a/4
2
1
1
1
1
V3
V3
2
2
(0, -1)
2
7/u = . 06
60° = x/3
120°
= 2 x/3
315° = 7 x/4
300° = 5 x/3
135° = 3 n/4
270° = 3 x/2
240 ° = 4 x/3

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