Use the equation for heat absorbed/lost to calculate the answer to the below question. Show as much work as possible and make sure to put the correct answer (with units) in the box provided. Equation: Q=mc△TQ=mc△T A 500.0 g piece of aluminum at 100° C is placed in 300ml of water. While in the water, the aluminum then cools to 30°C. Calculate the amount of heat lost by the aluminum. The specific heat of water is 4.18 J/g ∘∘C and the specific heat of aluminum is 0.90 J/g ∘∘C Remember: One ml = one gram. Neat handwriteing pleasee thank youuuu
Use the equation for heat absorbed/lost to calculate the answer to the below question. Show as much work as possible and make sure to put the correct answer (with units) in the box provided. Equation: Q=mc△TQ=mc△T A 500.0 g piece of aluminum at 100° C is placed in 300ml of water. While in the water, the aluminum then cools to 30°C. Calculate the amount of heat lost by the aluminum. The specific heat of water is 4.18 J/g ∘∘C and the specific heat of aluminum is 0.90 J/g ∘∘C Remember: One ml = one gram. Neat handwriteing pleasee thank youuuu
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Use the equation for heat absorbed/lost to calculate the answer to the below question. Show as much work as possible and make sure to put the correct answer (with units) in the box provided.
Equation: Q=mc△TQ=mc△T
A 500.0 g piece of aluminum at 100° C is placed in 300ml of water. While in the water, the aluminum then cools to 30°C. Calculate the amount of heat lost by the aluminum. The specific heat of water is 4.18 J/g ∘∘C and the specific heat of aluminum is 0.90 J/g ∘∘C
Remember: One ml = one gram.
Neat handwriteing pleasee thank youuuu
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