Use the equation E x" for |x| < 1 to expand the function in a power series with center c = -7. %D n=0

Calculus: Early Transcendentals
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Power Series Expansion with Center \( c = -7 \)

To expand the function \( \frac{7}{1-x} \) in a power series with the center \( c = -7 \), use the equation:

\[ 
\frac{1}{1-x} = \sum_{n=0}^{\infty} x^n \quad \text{for} \quad |x| < 1 
\]

Since we want to expand \( \frac{7}{1-x} \), we realize that it can be expressed as 

\[ 
7 \cdot \frac{1}{1-x} 
\]

Therefore, we substitute \( 7 \cdot \sum_{n=0}^{\infty} x^n \) for \( \frac{7}{1-x} \):

\[ 
\frac{7}{1-x} = 7 \sum_{n=0}^{\infty} x^n 
\]

Given that the center of the power series is \( c = -7 \), which implies a shift in the variable \(x\):

\[ 
x \rightarrow (x + 7) 
\]

This leads to the expansion:

\[ 
\frac{7}{1-(x + 7)} = 7 \sum_{n=0}^{\infty} (x + 7)^n
\]

However, the following expression shown is incorrect:

\[ 
\frac{7}{1-x} = \sum_{n=0}^{\infty} 8^{1-n} (7 + x)^n 
\]

The correct power series expansion should be:

\[ 
\frac{7}{1-(x + 7)} = 7 \sum_{n=0}^{\infty} (x + 7)^n 
\]

Keep in mind the conditions under which this series converges: 

\[ 
|x + 7| < 1 
\]
Transcribed Image Text:--- ### Power Series Expansion with Center \( c = -7 \) To expand the function \( \frac{7}{1-x} \) in a power series with the center \( c = -7 \), use the equation: \[ \frac{1}{1-x} = \sum_{n=0}^{\infty} x^n \quad \text{for} \quad |x| < 1 \] Since we want to expand \( \frac{7}{1-x} \), we realize that it can be expressed as \[ 7 \cdot \frac{1}{1-x} \] Therefore, we substitute \( 7 \cdot \sum_{n=0}^{\infty} x^n \) for \( \frac{7}{1-x} \): \[ \frac{7}{1-x} = 7 \sum_{n=0}^{\infty} x^n \] Given that the center of the power series is \( c = -7 \), which implies a shift in the variable \(x\): \[ x \rightarrow (x + 7) \] This leads to the expansion: \[ \frac{7}{1-(x + 7)} = 7 \sum_{n=0}^{\infty} (x + 7)^n \] However, the following expression shown is incorrect: \[ \frac{7}{1-x} = \sum_{n=0}^{\infty} 8^{1-n} (7 + x)^n \] The correct power series expansion should be: \[ \frac{7}{1-(x + 7)} = 7 \sum_{n=0}^{\infty} (x + 7)^n \] Keep in mind the conditions under which this series converges: \[ |x + 7| < 1 \]
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