Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Topic: Proving Limits Using the Epsilon-Delta Definition**
Use the \(\varepsilon - \delta\) definition of a limit to prove:
\[
\lim_{(x,y) \to (0,0)} \frac{xy}{\sqrt{x^2 + y^2}} = 0
\]
**Explanation:**
This statement asks to prove a two-variable limit using the epsilon-delta (\(\varepsilon - \delta\)) definition. The expression \(\frac{xy}{\sqrt{x^2 + y^2}}\) must approach 0 as the point \((x, y)\) approaches \((0, 0)\).
In the context of two variables, we say the limit of \(f(x, y)\) as \((x, y) \to (0, 0)\) is \(L\) if for every \(\varepsilon > 0\), there exists a \(\delta > 0\) such that if \(0 < \sqrt{x^2 + y^2} < \delta\), then \(|f(x, y) - L| < \varepsilon\).
Here, you need to demonstrate that:
For any \(\varepsilon > 0\), a \(\delta > 0\) exists such that if \(0 < \sqrt{x^2 + y^2} < \delta\), then:
\[
\left| \frac{xy}{\sqrt{x^2 + y^2}} - 0 \right| < \varepsilon
\]
This involves manipulating the inequality and finding conditions in terms of \(\delta\) to ensure that the expression can be made arbitrarily small, hence showing it approaches zero near \((0, 0)\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F091d1626-f44c-463a-bb52-1255cc41a5c6%2F592c723f-4c9f-4b31-bb1e-004a197174a4%2F3o0345g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Topic: Proving Limits Using the Epsilon-Delta Definition**
Use the \(\varepsilon - \delta\) definition of a limit to prove:
\[
\lim_{(x,y) \to (0,0)} \frac{xy}{\sqrt{x^2 + y^2}} = 0
\]
**Explanation:**
This statement asks to prove a two-variable limit using the epsilon-delta (\(\varepsilon - \delta\)) definition. The expression \(\frac{xy}{\sqrt{x^2 + y^2}}\) must approach 0 as the point \((x, y)\) approaches \((0, 0)\).
In the context of two variables, we say the limit of \(f(x, y)\) as \((x, y) \to (0, 0)\) is \(L\) if for every \(\varepsilon > 0\), there exists a \(\delta > 0\) such that if \(0 < \sqrt{x^2 + y^2} < \delta\), then \(|f(x, y) - L| < \varepsilon\).
Here, you need to demonstrate that:
For any \(\varepsilon > 0\), a \(\delta > 0\) exists such that if \(0 < \sqrt{x^2 + y^2} < \delta\), then:
\[
\left| \frac{xy}{\sqrt{x^2 + y^2}} - 0 \right| < \varepsilon
\]
This involves manipulating the inequality and finding conditions in terms of \(\delta\) to ensure that the expression can be made arbitrarily small, hence showing it approaches zero near \((0, 0)\).
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