Use the Divergence Theorem to evaluate / F. ds where and S is the boundary of the sphere x² + y² + z² = 4 oriented by the outward normal. The surface integral equals F = = (10x4, 3yz6, -40x³z)

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Chapter2: Second-order Linear Odes
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### Using the Divergence Theorem in Multivariable Calculus

In this example, we will use the Divergence Theorem to evaluate the surface integral of a vector field **F** over a closed surface **S**. Specifically, we will compute the following integral:

\[ \iint_S \mathbf{F} \cdot d\mathbf{S} \]

where the vector field \(\mathbf{F}\) is defined as:

\[ \mathbf{F} = \left\langle 10x^4, 3yz^6, -40x^3z \right\rangle \]

and **S** is the boundary of the sphere described by the equation:

\[ x^2 + y^2 + z^2 = 4 \]

### Given Information

- \(\mathbf{F} = \left\langle 10x^4, 3yz^6, -40x^3z \right\rangle\)
- \(S\) is the sphere \(x^2 + y^2 + z^2 = 4\) oriented by the outward normal.

### Objective

To find the value of the surface integral:

\[ \iint_S \mathbf{F} \cdot d\mathbf{S} \]

using the Divergence Theorem.

The Divergence Theorem states:

\[ \iint_S \mathbf{F} \cdot d\mathbf{S} = \iiint_V \mathbf{\nabla} \cdot \mathbf{F} \, dV \]

where \(V\) is the volume enclosed by \(S\).

### Applying the Divergence Theorem

To proceed, we need to calculate the divergence of the vector field \(\mathbf{F}\):

\[ \mathbf{\nabla} \cdot \mathbf{F} = \frac{\partial}{\partial x} (10x^4) + \frac{\partial}{\partial y} (3yz^6) + \frac{\partial}{\partial z} (-40x^3z) \]

1. Calculate each partial derivative:
   - \(\frac{\partial}{\partial x} (10x^4) = 40x^3\)
   - \(\frac{\partial}{\partial y} (3yz^6) = 3z^6\)
   - \(\frac{\partial}{\partial z
Transcribed Image Text:### Using the Divergence Theorem in Multivariable Calculus In this example, we will use the Divergence Theorem to evaluate the surface integral of a vector field **F** over a closed surface **S**. Specifically, we will compute the following integral: \[ \iint_S \mathbf{F} \cdot d\mathbf{S} \] where the vector field \(\mathbf{F}\) is defined as: \[ \mathbf{F} = \left\langle 10x^4, 3yz^6, -40x^3z \right\rangle \] and **S** is the boundary of the sphere described by the equation: \[ x^2 + y^2 + z^2 = 4 \] ### Given Information - \(\mathbf{F} = \left\langle 10x^4, 3yz^6, -40x^3z \right\rangle\) - \(S\) is the sphere \(x^2 + y^2 + z^2 = 4\) oriented by the outward normal. ### Objective To find the value of the surface integral: \[ \iint_S \mathbf{F} \cdot d\mathbf{S} \] using the Divergence Theorem. The Divergence Theorem states: \[ \iint_S \mathbf{F} \cdot d\mathbf{S} = \iiint_V \mathbf{\nabla} \cdot \mathbf{F} \, dV \] where \(V\) is the volume enclosed by \(S\). ### Applying the Divergence Theorem To proceed, we need to calculate the divergence of the vector field \(\mathbf{F}\): \[ \mathbf{\nabla} \cdot \mathbf{F} = \frac{\partial}{\partial x} (10x^4) + \frac{\partial}{\partial y} (3yz^6) + \frac{\partial}{\partial z} (-40x^3z) \] 1. Calculate each partial derivative: - \(\frac{\partial}{\partial x} (10x^4) = 40x^3\) - \(\frac{\partial}{\partial y} (3yz^6) = 3z^6\) - \(\frac{\partial}{\partial z
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