Use the definitions of even and odd numbers to justify your answers for (a)-(c). Assume that c is a particular integer. (a) Is -8c an even integer? 2(-4c) + 1 and -4c is an integer. Yes, because -8c = 2(-4c) and -4c is an integer. Yes, because -8c = No, because -8c = 2(-4c) and -4c is an integer. !3! No, because -8c 2(-4c) +1 and -4c is an integer. %3D (b) Is 8c + 7 an odd integer? Yes, because 8c + 7 = 2(4c + 3) + 1 and 4c + 3 is an integer. Yes, because 8c + 7 = 2(4c + 3) and 4c + 3 is an integer. No, because 8c + 7 = 2(4c + 3) + 1 and 4c + 3 is an integer. O No, because 8c + 7 = 2(4c + 3) and 4c + 3 is an integer. (c) Is (c? + 3) - (c? - 3) - 6 an even integer? Yes, because (c2 + 3) - (c2 - 3) - 6 - 2(0) and 0 is an integer. O Yes, because (c2 + 3) - (c2 - 3) - 6 = 2(0) + 1 and 0 is an integer. No, because (c2 + 3) - (c2 - 3) - 6 = 2(0) and 0 is an integer. No, because (c2 + 3) - (c2 - 3) - 6 = 2(0) + 1 and 0 is an integer.
Use the definitions of even and odd numbers to justify your answers for (a)-(c). Assume that c is a particular integer. (a) Is -8c an even integer? 2(-4c) + 1 and -4c is an integer. Yes, because -8c = 2(-4c) and -4c is an integer. Yes, because -8c = No, because -8c = 2(-4c) and -4c is an integer. !3! No, because -8c 2(-4c) +1 and -4c is an integer. %3D (b) Is 8c + 7 an odd integer? Yes, because 8c + 7 = 2(4c + 3) + 1 and 4c + 3 is an integer. Yes, because 8c + 7 = 2(4c + 3) and 4c + 3 is an integer. No, because 8c + 7 = 2(4c + 3) + 1 and 4c + 3 is an integer. O No, because 8c + 7 = 2(4c + 3) and 4c + 3 is an integer. (c) Is (c? + 3) - (c? - 3) - 6 an even integer? Yes, because (c2 + 3) - (c2 - 3) - 6 - 2(0) and 0 is an integer. O Yes, because (c2 + 3) - (c2 - 3) - 6 = 2(0) + 1 and 0 is an integer. No, because (c2 + 3) - (c2 - 3) - 6 = 2(0) and 0 is an integer. No, because (c2 + 3) - (c2 - 3) - 6 = 2(0) + 1 and 0 is an integer.
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter2: Working With Real Numbers
Section2.1: Basic Assumptions
Problem 37WE
Related questions
Question

Transcribed Image Text:Use the definitions of even and odd numbers to justify your answers for (a)-(c). Assume that c is a particular integer.
(a) Is -8c an even integer?
2(-4c) + 1 and -4c is an integer.
Yes, because -8c = 2(-4c) and -4c is an integer.
Yes, because -8c =
No, because -8c = 2(-4c) and -4c is an integer.
!3!
No, because -8c 2(-4c) + 1 and -4c is an integer.
%3D
(b) Is 8c + 7 an odd integer?
Yes, because 8c + 7 = 2(4c + 3) + 1 and 4c + 3 is an integer.
Yes, because 8c + 7 = 2(4c + 3) and 4c + 3 is an integer.
No, because 8c +7 = 2(4c + 3) + 1 and 4c + 3 is an integer.
O No, because 8c + 7 = 2(4c + 3) and 4c + 3 is an integer.
(c) Is (c? + 3) - (c2 - 3) - 6 an even integer?
Yes, because (c2 + 3) - (c2 - 3) - 6 - 2(0) and 0 is an integer.
O Yes, because (c2 + 3) - (c2 - 3) - 6 = 2(0) + 1 and 0 is an integer.
No, because (c2 + 3) - (c2 - 3) - 6 = 2(0) and 0 is an integer.
No, because (c2 + 3) - (c2 - 3) - 6 = 2(0) + 1 and 0 is an integer.
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