Use the data on the nonconformances for a period of 10 days to complete (a) through (c). Day Sample Size Nonconformances Day Sample Size Nonconformances Full data set 8 6 15 18 12 13 15 12345 150 150 150 150 150 14 6 15 20 879 9 10 150 150 150 150 150 a. On what day is the proportion of nonconformances largest? smallest? The proportion of nonconformances is the largest on day The proportion of nonconformances is the smallest on day b. What are the LCL and UCL? LCL = (Round to five decimal places as needed.) ...

MATLAB: An Introduction with Applications
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Use the data on the nonconformances for a period of 10 days to complete (a) through (c).
Day Sample Size Nonconformances Day Sample Size Nonconformances Full data set
1
6
2345
150
150
150
150
150
84652
14
LCL =
15
20
989
10
150
150
150
150
150
The proportion of nonconformances is the smallest on day
b. What are the LCL and UCL?
-0
(Round to five decimal places as needed.)
15
i W N 8 G
18
12
a. On what day is the proportion of nonconformances largest? smallest?
The proportion of nonconformances is the largest on day
13
15
Transcribed Image Text:Use the data on the nonconformances for a period of 10 days to complete (a) through (c). Day Sample Size Nonconformances Day Sample Size Nonconformances Full data set 1 6 2345 150 150 150 150 150 84652 14 LCL = 15 20 989 10 150 150 150 150 150 The proportion of nonconformances is the smallest on day b. What are the LCL and UCL? -0 (Round to five decimal places as needed.) 15 i W N 8 G 18 12 a. On what day is the proportion of nonconformances largest? smallest? The proportion of nonconformances is the largest on day 13 15
Use the data on the nonconformances for a period of 10 days to complete (a) through (c).
Day Sample Size Nonconformances Day Sample Size Nonconformances Full data set
1
2
3
4
5
150
150
150
150
150
846520
14
15
6789
10
UCL =
(Round to five decimal places as needed.)
c. Are there any special causes of variation?
150
150
150
150
150
15 18 12 13 15
O A. The nonconformance varies from day to day. Therefore, there does not appear to be any special causes of variation.
B. The nonconformance varies from day to day. Therefore, there does appear to be at least one special cause of variation.
OC. The proportions are not within control limits. Therefore, there does appear to be at least one special cause of variation.
D. The proportions are within control limits. Therefore, there does not appear to be any special causes of variation.
Transcribed Image Text:Use the data on the nonconformances for a period of 10 days to complete (a) through (c). Day Sample Size Nonconformances Day Sample Size Nonconformances Full data set 1 2 3 4 5 150 150 150 150 150 846520 14 15 6789 10 UCL = (Round to five decimal places as needed.) c. Are there any special causes of variation? 150 150 150 150 150 15 18 12 13 15 O A. The nonconformance varies from day to day. Therefore, there does not appear to be any special causes of variation. B. The nonconformance varies from day to day. Therefore, there does appear to be at least one special cause of variation. OC. The proportions are not within control limits. Therefore, there does appear to be at least one special cause of variation. D. The proportions are within control limits. Therefore, there does not appear to be any special causes of variation.
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