Use the data in the following table, which lists drive-thru order accuracy at popular fast food chains. Assume that orders are randomly selected from those included in the tableDrive-thru RestaurantC.235D.128315265Order Accurate375535Order Not Accurateone order is selected, find the probability of getting an order from restaurant A or D or an order that is not accurate......e probability of getting an order from restaurant A or D or an order that is not accurate isund to three decimal places as needed.)More(I'1)olve thisView an exampleGet more helpClear allCheck answer

The table represents drive-thru order accuracy at popular fast food chains. Drive-thru Restaurant A B C D Order Accurate 315 265 235 128 Order Not Accurate 37 55 35 10 If an restaurant is selected at random then total number of outcomes in the sample space, n(S) = 315+265+235+128+37+55+35+10 = 1080 Define the events, X : The order is from restaurant A Y : The order is from restaurant D Z : The order is not accurate From the table, number of orders from restaurant A , n(X) = 315+37 = 352 number of orders from restaurant D, n(Y) = 128+10 = 138 number of orders are not accurate , n(Z) = 37+55+35+10 = 137 number of orders from restaurant A and not accurate, n(X∩Z) = 37 number of orders from restaurant D and not accurate, n(Y∩Z) = 10 number of orders from restaurant A and D , n(X∩Y) = 0 [as the events are disjoint] number of orders from restaurant A and D and not accurate = 0 [As X and Y are disjoint] number of order from restaurant A or D or an order that is not accurate, n(X∪Y∪Z)= n(X) + n(Y) + n(Z) - n(X∩Y) - n(X∩Z) - n(Y∩Z) + n(X∩Y∩Z)=352+138+137 - 37 - 10=580To find, P(getting an order from restaurant A or D or an order that is not accurate) =P(X ∪ Y ∪ Z)= n(X ∪ Y ∪ Z)n(S)=5801080=0.537