Use the data in Problem P11-4A for the following reaction. Th elementary, irreversible, organic liquid-phase reaction А +В —С is carried out in a flow reactor. An equal molar feed in A and B enters at 27°C, and the volumetric flow rate is 2 dm/s and CA0 = 0.1 kmol/m³. ´A0 Additional information: H° (273 K) = – 20 kcal/mol, H(273 K) = – 15 kcal/mol, HE (273 K) = -41 kcal/mol CP, = CP3 = 15 cal/mol ·K CP. = 30 cal/mol · K dm3 k = 0.01 at 300 K E = 10,000 cal/mol mol ·s mc = 50g/s CPo = 1cal/g/K Ua = 20 cal/m /s/K %3D Tạo = 450K (a) Calculate the conversion when the reaction is carried out adiabatically in one 500-dm³ CSTR and then compare the results with the two adiabatic 250-dm³ CSTRS in series. The reversible reaction (part (d) of P11-4A) is now carried out in a PFR with a heat exchanger. Plot and then analyze X, Xe, T, T, Q,, Qe, and the rate, –ra, for the following cases: (b) Constant heat-exchanger temperature Ta
Use the data in Problem P11-4A for the following reaction. Th elementary, irreversible, organic liquid-phase reaction А +В —С is carried out in a flow reactor. An equal molar feed in A and B enters at 27°C, and the volumetric flow rate is 2 dm/s and CA0 = 0.1 kmol/m³. ´A0 Additional information: H° (273 K) = – 20 kcal/mol, H(273 K) = – 15 kcal/mol, HE (273 K) = -41 kcal/mol CP, = CP3 = 15 cal/mol ·K CP. = 30 cal/mol · K dm3 k = 0.01 at 300 K E = 10,000 cal/mol mol ·s mc = 50g/s CPo = 1cal/g/K Ua = 20 cal/m /s/K %3D Tạo = 450K (a) Calculate the conversion when the reaction is carried out adiabatically in one 500-dm³ CSTR and then compare the results with the two adiabatic 250-dm³ CSTRS in series. The reversible reaction (part (d) of P11-4A) is now carried out in a PFR with a heat exchanger. Plot and then analyze X, Xe, T, T, Q,, Qe, and the rate, –ra, for the following cases: (b) Constant heat-exchanger temperature Ta
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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just 12-7b please

Transcribed Image Text:P12-7B Use the data in Problem P11-4Ą for the following reaction.
Th elementary, irreversible, organic liquid-phase reaction
А + В —>С
is carried out in a flow reactor. An equal molar feed in A and B enters at 27°C, and the volumetric flow
rate is 2 dm/s and CA0 = 0.1 kmol/m³.
Additional information:
H (273 K) = –20 kcal/mol, H(273 K) = – 15 kcal/mol,
HE (273 K) = -41 kcal/mol
15 cal/mol K Ср — 30 саl/mol K
CPB
CPA
%|
dm
k = 0.01
at 300 K E = 10,000 cal/mol
mol ·s
mc = 50g/s
CP = 1cal/g/K
Ua = 20 cal/m /s/K
T.o = 450K
Cool
(a) Calculate the conversion when the reaction is carried out adiabatically in one 500-dm3 CSTR and
then compare the results with the two adiabatic 250-dm³ CSTRS in series.
The reversible reaction (part (d) of P11-4A) is now carried out in a PFR with a heat exchanger. Plot
and then analyze X, Xe, T, Tạ, Qr, Qg, and the rate, –ra, for the following cases:
(b) Constant heat-exchanger temperature T.
(c) Co-current heat exchanger T, (Ans.: At V = 10 m³ then X = 0.36 and T = 442 K)
(d) Countercurrent heat exchanger T. (Ans.: At V = 10 m³ then X = 0.364 and T = 450 K)
(e) Adiabatic operation
(f) Make a table comparing all your results (e.g., X, Xe, T, T,). Write a paragraph describing what you
find.
%3D
(g) Plot Q, and Ta as a function of V necessary to maintain isothermal operation.

Transcribed Image Text:P11-4, The elementary, irreversible, organic liquid-phase reaction
A+B→C
is carried out adiabatically in a flow reactor. An equal molar feed in A and B enters at 27°C, and the volu-
metric flow rate is 2 dm³/s and CA0 = 0.1 kmol/m³.
Additional information:
H(273 K) = – 20 kcal/mol, H (273 K) = - 15 kcal/mol,
HE(273 K) = -41 kcal/mol
CPA
= 15 cal/mol ·K
PB
= 30 cal/mol ·K
CPc
dm3
k = 0.01
at 300 K
E = 10,000 cal/mol
mol ·s
PFR
(a) Plot and then analyze the conversion and temperature as a function of PFR volume up to where
X = 0.85. Describe the trends.
(b) What is the maximum inlet temperature one could have so that the boiling point of the liquid
(550 K) would not be exceeded even for complete conversion?
(c) Plot the heat that must be removed along the reactor (Q vs. V) to maintain isothermal operation.
(d) Plot and then analyze the conversion and temperature profiles up to a PFR reactor volume of 10 dm3
for the case when the reaction is reversible with Kc = 10 m³/kmol at 450 K. Plot the equilibrium
conversion profile. How are the trends different than part (a)? (Ans.: When V = 10 dm³ then
X = 0.0051, Xeg = 0517)
CSTR
(e) What is the CSTR volume necessary to achieve 90% conversion?
BR
(f) The reaction is next carried out in a 25 dm³ batch reactor charged with N
number of moles of A, N, the conversion, and the temperature as a function of time.
= 10 moles. Plot the
AO
D11 E
Th
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