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- A hospital claims that the average length of patient confinement is 5 days. A study of the length of patient confinement of 36 people showed a mean of 6.2 and s = 5.2. Does this data support the hospital’s claim? Use α = 0.01.• The paper referenced in the previous exercise gave the accompanying data on the at which smoking started for a sample of 1031 men who smoked low-tar cigarettes. 12.8 also age Eregu enoA physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =
- An automobile dealer conducted a test to determine if the time in minutes needed to complete a minor engine tune-up depends on whether a computerized engine analyzer or an electronic analyzer is used. Because tune-up time varies among compact, intermediate, and full-sized cars, the three types of cars were used as blocks in the experiment. The data obtained follow. Analyzer Computerized Electronic Compact 50 41 Car Intermediate 56 44 Full-sized 62 47 Use a = 0.05 to test for any significant differences. State the null and alternative hypotheses. O Ho: Hcompact * HIntermediate * HFull-sized Ha: "Compact = HIntermediate = 4Full-sized O Ho: HComputerized * HElectronic Ha: HComputerized = HElectronic O Ho: HComputerized = HElectronic Ha: "Computerized * HElectronic O Ho: HComputerized = HElectronic = "Compact = HIntermediate = "Full-sized H.: Not all the population means are equal. O Ho: HCompact = HIntermediate = HFull-sized Hai H compact * HIntermediate * HFull-sized Find the value of…A local veterinarian uses Z-scores to determine if newborn puppies of certain breeds are severely underweight, underweight, overweight, severely overweight, or within a typical weight range for their breed. Z-score Diagnosis Severely underweight Between -4.0 and -3.0 Underweight Less than -4.0 Between -3.0 and 3.0 Within the normal range Between 3.0 and 4.0 Overweight Severely overweight Greater than 4.0 Breed Mean (pounds) Standard deviation (pounds) Siberian Husky 23.2 2.5 Golden Retriever 31.5 2.1 Chow Chow 18.5 2.4 Shiba Inu 13.9 1.2 (a) What values would be considered to be normal for a hypothetical Siberian Husky puppy? Between and Enter an integer or decimal number (more. Report these answers to one decimal place (nearest tenth). (b) Show calculations and explain your reasoning.Use the Stata output below to answer the following question. The data used in this analysis is from a sample of airlines. The variables used are: fare-avg price of a one-way fare, in dollars dist- distance of the flight, in miles .reg fare ldist. Source Model Residual 551.391705 Total lfare SS ldist _cons 875.094374 df The OLS results suggest that 1 323.702668 120024315 4,594 MS Coef. Std. Err. 4,595 190444913 Number of obs F(1, 4594) Prob > F R-squared Adj R-squared Root MSE t P>|t| .4025646 .0077517 51.93 0.000 2.399834 .0521601 46.01 0.000 4,596 2696.98 0.0000 0.3699 0.3698 .34645 [95% Conf. Intervall .3873676 .4177617 2.297575 2.502093 a 1% increase in distance is associated with approximately a $.40 increase in the price of the fare. a 1% increase in distance is associated with approximately a .40% increase in the price of the fare. a 1% increase in distance is associated with approximately a 40 % increase in the price of the fare. None of the above.
- You are conducting a study to see if the accuracy rate for fingerprint identification is significantly different from 0.51. Thus you are performing a two-tailed test. Your sample data produce the test statistic - 2.153. Find the p-value accurate to Z = - 4 decimal places. p-valueTime to Complete the Course Right 45 47 50 49 50 50 48 44 Left | 45 | 43 48 47 50 52 | 44 42 Assume a Normal distribution. What can be concluded at the the a = 0.01 level of significance level of significance? For this study, we should use t-test for the difference between two dependent population means a. The null and alternative hypotheses would be: p1 p2 Ні: p1 p2 b. The test statistic t v v = 1.199 (please show your answer to 3 decimal places.) c. The p-value = [1338 your answer to 4 decimal places.) d. The p-value is > va e. Based on this, we should fail to reject f. Thus, the final conclusion is that ... * (Please show v the null hypothesis. O The results are statistically insignificant at a = 0.01, so there is insufficient evidence to conclude that the population mean time to complete the obstacle course with a patch overA survey of the population of 51 students in Psych 311 asks how many credits students are taking and obtains the following normally-distributed results: ∑ X= 686 and ∑X2= 9832.92. Using this information, answer the following three questions. What is the percentile rank of a student who is enrolled in 15 credits? (Hint: This is the same thing as asking “what percentage of students is enrolled in 15 credits or less?”) MUST SHOW WORK FOR THIS PROBLEM What percentage of students are enrolled in between 12 and 18 credits? (MUST SHOW WORK FOR THIS PROBLEM) What is the 25th percentile? (Hint: This is the same as asking what score separates the bottom 25% of the distribution from the top 75%.) MUST SHOW WORK FOR THIS PROBLEM
- The herbal supplement ginkgo biloba is advertised as producing an increase in physical strength and stamina. To test this claim, a sample of n = 120 adults is obtained and each person is instructed to take the regular daily dose of the herb for a period of 30 days. At the end of the 30 days each person is tested on a standard treadmill task for which the average age-adjusted score is μ = 15. The individuals in the sample produce a mean score of M = 17.4 with SS = 1260. Are these data sufficient to conclude that the herb had a statistically significant effect? Conduct as a two-tailed test, using all hypothesis steps with p < .05. BONUS POINTS: Calculate the 95% confidence intervalThe local Hannaford was tracking the proportion of customers who bought flour in their stores. In mid-March they found that 65% of customers were buying flour when it was available. They want to know if that percentage has decreased now that flour is more readily available. Their hypotheses are: Ho: p 2 .65 and Ha: p < .65. They sample 200 customers and found that 120 of them bought flour. What is the computed test statistic? Calculate the z or t, whichever is appropriate, and give the result rounded to 2 decimal places. If it's a negative number, put the negative sign before the number with no spaces between it and the number.