Use the data below on the height of fathers and their first son. Test the claim that there is no difference in heights between fathers and their first son. Use a 5% level of significance. Assume all requirements are met.What is the P-value? Will the null hypothesis be rejected? In general, are first sons the same height as their fathers? Height of father72666970707070756565Height of son74686971727072746565

The data shows the height of fathers and their first son.1. The claim is that there is no difference in heights between fathers and their first son. The hypothesis is, Null hypothesis: H0:μd=0 Alternative hypothesis: H1:μd≠0 The P-value is obtained by using the EXCEL procedure as follows: Enter the data. Select Data > Data Analysis >t-Test: Paired Two Sample for Means> OK. Enter Variable 1 Range as A1:A11. Enter Variable 2 Range as B1:B11. Enter Hypothesized Mean Difference as 0. Mark Labels in First Row. Click OK. The output is, From the output, the P-value for two-tail test is 0.0528. Thus, the P-value is 0.0528.2. Decision rule: If P-value ≤ α, then reject the null hypothesis. Conclusion: The P-value (=0.0528) is greater than the level of significance (=0.05). Based on decision rule, fail to reject the null hypothesis. Thus, the null hypothesis is not rejected.3. Since the null hypothesis is not rejected indicating that the first sons height is same as fathers. Thus, the first sons heights are the same height as their fathers.