Use the cosine of a sum and cosine of a difference identities to find cos (s + t) and cos (s - t). 12 and sint= 13 3 sin s = s in quadrant IV and t in quadrant II 5 cos (s + %3D (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) cos (s - t) = %3D (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)
Use the cosine of a sum and cosine of a difference identities to find cos (s + t) and cos (s - t). 12 and sint= 13 3 sin s = s in quadrant IV and t in quadrant II 5 cos (s + %3D (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) cos (s - t) = %3D (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 10E
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![Use the cosine of a sum and cosine of a difference identities to find cos (s+ t) and cos (s- t).
12
3
sin s =
and sint==, s in quadrant IV and t in quadrant II
13
cos (s +t) =
(Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)
cos (s - t) =
(Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F96e8a255-6b70-420c-b5ef-4b46ae1f8d5e%2Fa8890fdf-d056-4659-9e79-5659031ebc3f%2F5pmhjgs_processed.png&w=3840&q=75)
Transcribed Image Text:Use the cosine of a sum and cosine of a difference identities to find cos (s+ t) and cos (s- t).
12
3
sin s =
and sint==, s in quadrant IV and t in quadrant II
13
cos (s +t) =
(Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)
cos (s - t) =
(Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)
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