Use the confidence interval to find the margin of error and the sample mean. (1.62,2.00) The margin of error is (Round to two decimal places as needed.)
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A: given data p^ = 0.1691% ci E = 0.04n = ?
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Q: Use the confidence interval to find the estimated margin of error. Then find the sample mean. A…
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Q: Use the confidence interval to find the estimated margin of error. Then find the sample mean. A…
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Q: Use the confidence interval to find the estimated margin of error. Then find the sample mean. A…
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A: Given that Confidence interval=(1.44,1.98)
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A: Lower limit = 1.56 Upper limit = 1.96
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A: Use the given confidence interval to find the margin of error and the sample mean. (70.7,85.7)…
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A: Confidence interval is (2.5 ,3.1) Lower confidence Limit(LCL)=2.5 Upper Confidence Limit(UCL)=3.1
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A: The confidence interval is CI =(LB,UB) CI = (1.53,2.03)
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A: GIVEN DATA, c=0.90s=3.6n=18df=n-1=18-1=17margin of error: E=?
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A: Given Confidence interval is LL=1.6 UL=2.8 ME=?
Q: Use the confidence interval to find the estimated margin of error. Then find the sample mean. A…
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A: The margin of error is the most common term which we use in a confidence interval. It is the degree…
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Q: Use the given confidence interval to find the margin of error and the sample mean. (70.5,84.7)
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Q: Use the given confidence interval to find the margin of error and the sample mean. (4.81, 8.09)
A: The confidence interval is given by (4.81, 8.09)
Q: Use the confidence interval to find the margin of error and the sample mean. (1.59,1.95) The margin…
A: GivenConfidence interval is (1.59 , 1.95)Upper class limit = 1.95Lower class limit = 1.59
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- Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence interval of (2.3,3.1) when estimating the mean height (in centimeters) of a sample of seedlings. The estimated margin of error is The sample mean is BUse the confidence interval to find the margin of error and the sample mean. (1.54,1.88) The margin of error is 0.17. (Round to two decimal places as needed.) The sample mean is. (Type an integer or a decimal.)Use the formula in this example to determine the sample size, n.The estimated prevalence is 19%, and the desired confidence level is 93% with a margin of error of 4%. (Round your answer to the nearest integer.)n =
- Use the confidence interval to find the margin of error and the sample mean. (0.346,0.450) The margin of error is The sample mean is 9 五 0 SF10Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence interval of (4.2,5.4) when estimating the mean height (in centimeters) of a sample of seedlings. The estimated margin of error is The sample mean is Search 6 17 + & 87 lyn 8 9 DYWAN DDI 8 0 0 0Find the margin of error for the given values of c, s, and n. c= 0.90, s = 3.7, n= 22 Click the icon to view the t-distribution table. The margin of error is (Round to one decimal place as needed.)
- Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence interval of (1.9.3.1) when estimating the mean height (in centimeters) of a sample of seedlings. The estimated margin of error is The sample mean is7Use the confidence interval to find the margin of error and the sample mean. (0.384,0.480) The margin of error is The sample mean is Question Viewer
- Use the confidence interval to find the estimated margin of error. Then find the sample mean. A store manager reports a confidence interval of (41.6,81.0) when estimating the mean price (in dollars) for the population of textbooks. The estimated margin of error is enter your response here. (Type an integer or a decimal.)Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence interval of (2.8,4.6) when estimating the mean height (in centimeters) of a sample of seedlings. The estimated margin of error is The sample mean isUse the confidence interval to find the margin of error and the sample mean. (1.62,1.90) The margin of error is (Round to two decimal places as needed.) The sample mean is