Use the Comparison Test to determine if the following series converges or diverges. 1 Σ n=1 2 2n + 13 Choose the correct answer below. OA. The series is divergent because OB. The series is convergent because O D. O c. The series is convergent because The series is divergent because n 1 1 n 2 < 1 2 2n + 13 < 1 2 2n + 13 1 2 2n + 13 1 < < 2 2n + 13 1 8 · for all n and Σ 3 n=1 n ∞ for all n and Σ 1 8 · for all n and Σ 2 n 2 n n=1 1 1 -|♡c n is divergent. 3 -~c n=1 n 2 is convergent. is convergent. for all n and the harmonic series is divergent.
Use the Comparison Test to determine if the following series converges or diverges. 1 Σ n=1 2 2n + 13 Choose the correct answer below. OA. The series is divergent because OB. The series is convergent because O D. O c. The series is convergent because The series is divergent because n 1 1 n 2 < 1 2 2n + 13 < 1 2 2n + 13 1 2 2n + 13 1 < < 2 2n + 13 1 8 · for all n and Σ 3 n=1 n ∞ for all n and Σ 1 8 · for all n and Σ 2 n 2 n n=1 1 1 -|♡c n is divergent. 3 -~c n=1 n 2 is convergent. is convergent. for all n and the harmonic series is divergent.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Use the Comparison Test to determine if the following series converges or diverges.
1
Σ
n=1
2
2n + 13
Choose the correct answer below.
A. The series is divergent because
O B. The series is convergent because
D.
O c. The series is convergent because
The series is divergent because
n
1
1
2
n
<
1
2
2n + 13
1
2n²+ 13
<
1
2
2n + 13
<
<
1
2
2n + 13
1
3
n
∞
1
for all n and Σ is divergent.
2
n
n=1
n
∞
for all n and Σ
n=1 n
3
1
1
· for all n and Σ is convergent.
2
2
is convergent.
n=1 n
for all n and the harmonic series is divergent.
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