Use the Chain Rule to evaluate the partial derivative y = e³u sin(v). (Use symbolic notation and fractions where needed.) dg du\(u, v) Incorrect = 5.063 dg at the point (u, v) = (0, 6), where g(x, y) = x² − y², x = e³u cos(v), du

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Example Problem: Chain Rule Application in Multivariable Calculus**

Use the Chain Rule to evaluate the partial derivative \(\frac{\partial g}{\partial u}\) at the point \((u, v) = (0, 6)\), where \( g(x, y) = x^2 - y^2 \), \( x = e^{3u} \cos(v) \), and \( y = e^{3u} \sin(v) \).

(Use symbolic notation and fractions where needed.)

Given the equation:

\[ 
\frac{\partial g}{\partial u} \bigg|_{(u,v)}
\]

An incorrect value has been input:

\[ 
\frac{\partial g}{\partial u} \bigg|_{(u,v)} = 5.063
\]

Note: The highlighted red box with the word "Incorrect" indicates that the value 5.063 entered as the partial derivative is incorrect.

In solving this problem, be sure to apply the Chain Rule correctly to find the accurate derivative value.
Transcribed Image Text:**Example Problem: Chain Rule Application in Multivariable Calculus** Use the Chain Rule to evaluate the partial derivative \(\frac{\partial g}{\partial u}\) at the point \((u, v) = (0, 6)\), where \( g(x, y) = x^2 - y^2 \), \( x = e^{3u} \cos(v) \), and \( y = e^{3u} \sin(v) \). (Use symbolic notation and fractions where needed.) Given the equation: \[ \frac{\partial g}{\partial u} \bigg|_{(u,v)} \] An incorrect value has been input: \[ \frac{\partial g}{\partial u} \bigg|_{(u,v)} = 5.063 \] Note: The highlighted red box with the word "Incorrect" indicates that the value 5.063 entered as the partial derivative is incorrect. In solving this problem, be sure to apply the Chain Rule correctly to find the accurate derivative value.
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