Use the Cauchy-Schwarz inequality b = (1, z+u) to show that √√1 + (z + u)²√√1+z² ≥ 1+z² + zu. with equality only if u = 0. Hence show that /1 + (z + u)² − √√1 + z² ≥ zu √1+z² with a = (1,z) and

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Use the Cauchy-Schwarz inequality
b= (1, z+u) to show that
/1 + (z+u)² √√1+z² ≥ 1+z² + zu.
with equality only if u = 0. Hence show that
/1 + (z + u)² − √√1 + x² >
zu
√1+z²
with a =
(1,z) and
Transcribed Image Text:Use the Cauchy-Schwarz inequality b= (1, z+u) to show that /1 + (z+u)² √√1+z² ≥ 1+z² + zu. with equality only if u = 0. Hence show that /1 + (z + u)² − √√1 + x² > zu √1+z² with a = (1,z) and
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