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Use the calibration curve data provided to determine the entropy (ΔS, in J/K) associated with dissolving KNO3. please put the answer in this format: ____x10___power ___units *use correct sig figs

Use the calibration curve data provided to determine the entropy (ΔS, in J/K) associated with dissolving KNO3. please put the answer in this format: ____x10___power ___units *use correct sig figs

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Use the calibration curve data provided to determine the entropy (ΔS, in J/K) associated with dissolving KNO3.

please put the answer in this format: ____x10___power ___units

*use correct sig figs

### Thermodynamic Data for Solubility of Potassium Nitrate (KNO₃) This graph presents the relationship between the natural logarithm of the solubility product constant (\( \ln K_{sp} \)) of potassium nitrate (KNO₃) and the inverse of temperature (\(1/T\) in Kelvin\(^{-1}\)). #### Graph Description: - **Title**: Thermodynamic Data for Solubility of KNO₃ - **Y-Axis**: \( \ln K_{sp} \) - Range: 0 to 4 - **X-Axis**: \(1/T\) (K\(^{-1}\)) - Range: 0.003 to 0.00335 - **Data Points**: A series of plotted points showing the experimental data. - **Trend Line**: A dotted line running through the data points, representing a linear fit. - **Equation**: \( y = -5017x + 19.081 \) - **Correlation Coefficient**: \( R^2 = 0.9922 \), indicating a strong linear relationship. This graph effectively illustrates how the solubility of KNO₃ decreases with a decrease in temperature, as reflected by the positive slope of the linear relationship when plotted as \(\ln K_{sp}\) versus \(1/T\). The high \(R^2\) value suggests that the linear model provides a good fit for the data, indicating a strong inverse relationship between the solubility product and temperature.
Transcribed Image Text:### Thermodynamic Data for Solubility of Potassium Nitrate (KNO₃) This graph presents the relationship between the natural logarithm of the solubility product constant (\( \ln K_{sp} \)) of potassium nitrate (KNO₃) and the inverse of temperature (\(1/T\) in Kelvin\(^{-1}\)). #### Graph Description: - **Title**: Thermodynamic Data for Solubility of KNO₃ - **Y-Axis**: \( \ln K_{sp} \) - Range: 0 to 4 - **X-Axis**: \(1/T\) (K\(^{-1}\)) - Range: 0.003 to 0.00335 - **Data Points**: A series of plotted points showing the experimental data. - **Trend Line**: A dotted line running through the data points, representing a linear fit. - **Equation**: \( y = -5017x + 19.081 \) - **Correlation Coefficient**: \( R^2 = 0.9922 \), indicating a strong linear relationship. This graph effectively illustrates how the solubility of KNO₃ decreases with a decrease in temperature, as reflected by the positive slope of the linear relationship when plotted as \(\ln K_{sp}\) versus \(1/T\). The high \(R^2\) value suggests that the linear model provides a good fit for the data, indicating a strong inverse relationship between the solubility product and temperature.
Expert Solution
Step 1

Chemistry homework question answer, step 1, image 1

Step 2

Calculation for y-intercept:

y=-5017x+19.081

            At x = 0,

y=-5017(0)+19.081

y=19.081

 

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