: Use the Booth algorithm to multiply -5 by +7. Draw the schematic of hardware and show the contents of each section after each cycle/step.

Computer Networking: A Top-Down Approach (7th Edition)
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QUESTION: Use the Booth algorithm to multiply -5 by +7. Draw the schematic of hardware and show the contents of each section after each cycle/step.

 

*NOTE: PLEASE EXACTLY SOLVE LIKE THIS*

Show the 2’s complement multiplication using Booth’s algorithm

Multiplicand: +7       Multiplier: - 6

CYCLE
OPERATIONS
Content of A
Content of Q
Q.1
Comments, if any
Content of M
Initial Value
Initialization
0000
1010
Q.Q-1= 00
Сycle-1
Arithmetic Shift
0000
0101
QoQ-1= 10
right
(A Q Q.1)
Cycle-2
A= A-M
1001
0101
QoQ-1= 10
Shift right
1100
1010
1
QoQ-1= 01
(A QQ.1)
Сycle-3
A=A+M
0011
1010
1
QoQ-1= 01
0111
Shift right
0001
1101
QoQ.1= 10
(A QQ.1)
Cycle-4
A=A-M
1010
1101
QoQ-1= 10
Shift right
1101
0110
1
QoQ-1= 01
(A QQ.1)
Product is in: AQ pair: 11010110 in 2's complement since MSB is 1, to get magnitude, take 2's
complement of AQ: 00101001 + 1 = 00101010 = 42
Answer: - 42
Transcribed Image Text:CYCLE OPERATIONS Content of A Content of Q Q.1 Comments, if any Content of M Initial Value Initialization 0000 1010 Q.Q-1= 00 Сycle-1 Arithmetic Shift 0000 0101 QoQ-1= 10 right (A Q Q.1) Cycle-2 A= A-M 1001 0101 QoQ-1= 10 Shift right 1100 1010 1 QoQ-1= 01 (A QQ.1) Сycle-3 A=A+M 0011 1010 1 QoQ-1= 01 0111 Shift right 0001 1101 QoQ.1= 10 (A QQ.1) Cycle-4 A=A-M 1010 1101 QoQ-1= 10 Shift right 1101 0110 1 QoQ-1= 01 (A QQ.1) Product is in: AQ pair: 11010110 in 2's complement since MSB is 1, to get magnitude, take 2's complement of AQ: 00101001 + 1 = 00101010 = 42 Answer: - 42
M-1
М
n-bit adder
control logic
A.
Qa-1
Qo
Q-1
Transcribed Image Text:M-1 М n-bit adder control logic A. Qa-1 Qo Q-1
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