Use the bar graph below, which shows the highest level of education received by employees of a company, to find the probability that the highest level of education for an employee chosen at random is D. Number of employees 40- 35- 30- 25- 20- 15- 10- 6 Level of education. 35 25 B C 16 D E The probability that the highest level of education for an employee chose at random is D is. (Round to the nearest thousandth as needed.)
Use the bar graph below, which shows the highest level of education received by employees of a company, to find the probability that the highest level of education for an employee chosen at random is D. Number of employees 40- 35- 30- 25- 20- 15- 10- 6 Level of education. 35 25 B C 16 D E The probability that the highest level of education for an employee chose at random is D is. (Round to the nearest thousandth as needed.)
MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![### Understanding Probability through Educational Levels in a Company
Use the bar graph below, which shows the highest level of education received by employees of a company, to find the probability that the highest level of education for an employee chosen at random is D.
#### Graph Description
The bar graph has the following structure:
- **X-axis (horizontal):** Represents the level of education labeled from A to F.
- **Y-axis (vertical):** Represents the number of employees, with values ranging from 5 to 35.
Here is the detailed breakdown of the highest level of education received by the number of employees:
- **Level A:** 6 employees
- **Level B:** 25 employees
- **Level C:** 35 employees
- **Level D:** 16 employees
- **Level E:** 5 employees
- **Level F:** 1 employee
#### Calculating the Probability
The probability that the highest level of education for an employee chosen at random is level D can be calculated using the formula for probability:
\[ P(D) = \frac{\text{Number of employees with level D education}}{\text{Total number of employees}} \]
Total number of employees = 6 (A) + 25 (B) + 35 (C) + 16 (D) + 5 (E) + 1 (F) = 88
\[ P(D) = \frac{16}{88} \]
Simplify the fraction:
\[ P(D) = \frac{2}{11} \approx 0.182 \]
Round the result to the nearest thousandth:
\[ P(D) \approx 0.182 \]
**Answer:**
The probability that the highest level of education for an employee chosen at random is D is approximately **0.182**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F20a0be3e-3983-4420-aed0-1c62c53b9b01%2F6d58fcdb-5fed-47b3-9111-274d07ae7c61%2Fm7b3cih_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Understanding Probability through Educational Levels in a Company
Use the bar graph below, which shows the highest level of education received by employees of a company, to find the probability that the highest level of education for an employee chosen at random is D.
#### Graph Description
The bar graph has the following structure:
- **X-axis (horizontal):** Represents the level of education labeled from A to F.
- **Y-axis (vertical):** Represents the number of employees, with values ranging from 5 to 35.
Here is the detailed breakdown of the highest level of education received by the number of employees:
- **Level A:** 6 employees
- **Level B:** 25 employees
- **Level C:** 35 employees
- **Level D:** 16 employees
- **Level E:** 5 employees
- **Level F:** 1 employee
#### Calculating the Probability
The probability that the highest level of education for an employee chosen at random is level D can be calculated using the formula for probability:
\[ P(D) = \frac{\text{Number of employees with level D education}}{\text{Total number of employees}} \]
Total number of employees = 6 (A) + 25 (B) + 35 (C) + 16 (D) + 5 (E) + 1 (F) = 88
\[ P(D) = \frac{16}{88} \]
Simplify the fraction:
\[ P(D) = \frac{2}{11} \approx 0.182 \]
Round the result to the nearest thousandth:
\[ P(D) \approx 0.182 \]
**Answer:**
The probability that the highest level of education for an employee chosen at random is D is approximately **0.182**.
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