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Use the balanced equation provided to answer the following: 4 Fe +,3 02 --> 2 Fe203 For the following question, fill in the missing conversion factor: what mass of oxygen (02) is needed to produce 150 g Fe203 reacting with excess iron (Fe)? 155 g Fe,03 3 mol 02 32.00g 02 X X 2 mol Fe,03 1 mol 02 MM Fe: 55.85 g/mol MM Fe203: 159.70 g/mol MM O2: 32.00 g/mol

Use the balanced equation provided to answer the following: 4 Fe +,3 02 --> 2 Fe203 For the following question, fill in the missing conversion factor: what mass of oxygen (02) is needed to produce 150 g Fe203 reacting with excess iron (Fe)? 155 g Fe,03 3 mol 02 32.00g 02 X X 2 mol Fe,03 1 mol 02 MM Fe: 55.85 g/mol MM Fe203: 159.70 g/mol MM O2: 32.00 g/mol

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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MM O2: 32.00 g/mol O 2 mol Fe203 3 mol O2 3 mol O2 159.70 g Fe203 159.70 g Fe,O3 1 mol Fe203 1 mol Fe203 159.70 g Fe203 99+ c F5 PrtSc Insert F4 F6 F7 F8 F9 F10 F11 F12 & * 4 8. 9. T. Y U G H. L 图 5
Transcribed Image Text:MM O2: 32.00 g/mol O 2 mol Fe203 3 mol O2 3 mol O2 159.70 g Fe203 159.70 g Fe,O3 1 mol Fe203 1 mol Fe203 159.70 g Fe203 99+ c F5 PrtSc Insert F4 F6 F7 F8 F9 F10 F11 F12 & * 4 8. 9. T. Y U G H. L 图 5
Use the balanced equation provided to answer the following: 4 Fe +,3 02 --> 2 Fe203 For the following question, fill in the missing conversion factor: what mass of oxygen (02) is needed to produce 150g Fe203 reacting with excess iron (Fe)? 3 mol 02 32.00g 02 155 g Fe,03 ? 2 mol Fe,03 1 mol 02 MM Fe: 55.85 g/mol MM Fe203: 159.70 g/mol MM O2: 32.00 g/mol 99+ PrtSc Insert C F5 F10 F11 F12 F6 F7 F8 F4 * 24 %3D 5 7 6. Y U J +II P. 图 * CO |小
Transcribed Image Text:Use the balanced equation provided to answer the following: 4 Fe +,3 02 --> 2 Fe203 For the following question, fill in the missing conversion factor: what mass of oxygen (02) is needed to produce 150g Fe203 reacting with excess iron (Fe)? 3 mol 02 32.00g 02 155 g Fe,03 ? 2 mol Fe,03 1 mol 02 MM Fe: 55.85 g/mol MM Fe203: 159.70 g/mol MM O2: 32.00 g/mol 99+ PrtSc Insert C F5 F10 F11 F12 F6 F7 F8 F4 * 24 %3D 5 7 6. Y U J +II P. 图 * CO |小
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