Use the balanced equation provided to answer the following: 4 Fe +,3 02 --> 2 Fe203 For the following question, fill in the missing conversion factor: what mass of oxygen (02) is needed to produce 150 g Fe203 reacting with excess iron (Fe)? 155 g Fe,03 3 mol 02 32.00g 02 X X 2 mol Fe,03 1 mol 02 MM Fe: 55.85 g/mol MM Fe203: 159.70 g/mol MM O2: 32.00 g/mol

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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MM O2: 32.00 g/mol
O 2 mol Fe203
3 mol O2
3 mol O2
159.70 g Fe203
159.70 g Fe,O3
1 mol Fe203
1 mol Fe203
159.70 g Fe203
99+
c
F5
PrtSc
Insert
F4
F6
F7
F8
F9
F10
F11
F12
&
*
4
8.
9.
T.
Y
U
G
H.
L
图
5
Transcribed Image Text:MM O2: 32.00 g/mol O 2 mol Fe203 3 mol O2 3 mol O2 159.70 g Fe203 159.70 g Fe,O3 1 mol Fe203 1 mol Fe203 159.70 g Fe203 99+ c F5 PrtSc Insert F4 F6 F7 F8 F9 F10 F11 F12 & * 4 8. 9. T. Y U G H. L 图 5
Use the balanced equation provided to answer the following:
4 Fe +,3 02 --> 2 Fe203
For the following question, fill in the missing conversion factor: what mass of oxygen
(02) is needed to produce 150g Fe203 reacting with excess iron (Fe)?
3 mol 02
32.00g 02
155 g Fe,03
?
2 mol Fe,03
1 mol 02
MM Fe: 55.85 g/mol
MM Fe203: 159.70 g/mol
MM O2: 32.00 g/mol
99+
PrtSc
Insert
C
F5
F10
F11
F12
F6
F7
F8
F4
*
24
%3D
5
7
6.
Y
U
J
+II
P.
图
* CO
|小
Transcribed Image Text:Use the balanced equation provided to answer the following: 4 Fe +,3 02 --> 2 Fe203 For the following question, fill in the missing conversion factor: what mass of oxygen (02) is needed to produce 150g Fe203 reacting with excess iron (Fe)? 3 mol 02 32.00g 02 155 g Fe,03 ? 2 mol Fe,03 1 mol 02 MM Fe: 55.85 g/mol MM Fe203: 159.70 g/mol MM O2: 32.00 g/mol 99+ PrtSc Insert C F5 F10 F11 F12 F6 F7 F8 F4 * 24 %3D 5 7 6. Y U J +II P. 图 * CO |小
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