Use the attached Excel table to see the average cost of tuition by s (public four year college) and use the cost of tuition per year for in state students. ) USE every THI RD state START I NG WITH MT (MONTANA) since they are in order from low to high so we get a good sample of all 50 Do not count (skip) US (United States) or delete that row before you sta Notice that that US average is different -it is $9650. So our claim is that the average in-state tuition is more than $9410. You should have 16 states for public four year colleges in-state tuition. Name of State Cost of' Tuition (per year for in s1 MT 6410 NV 6910 NC 7200 NY 7710 OK 8030 IA 8270 LA 8900 IN 9200 MD 9370 ME 9690 AL 10040 HI 10670 RI 11410 SC 12190 Ml 12460 PA 13880 Form the hypotheses (null and alternative) and identify the claim Claim: Average in-state tuition is more than 9410. Ho: HO: μ =9410 Hα: HA: μ>9410 State the distribution and test statistic to be used. Normal distribution and test statistic 4pts. Find the sample mean to the nearest whole number. 9521 4 pts. Find the sample standard deviation to the nearest who le number. 2151 Find the value of the test statistic. To 3 decimal places 0.206 Compute and interpret the p-value. To 2 decimal places 0.42 Use the previous informat ion to sketch a picture of this situation. CLEARLY, label and sca le the horizonta l ax is and shade the region(s) corresponding to the p-value. 6pts. Make the decision to reject or to not reject the null hypothesis. Explain. Since P value is > 0.05 it is not significant, so do not reject the null hypothesis. 6pts. Form a conclusion written in terms of the original claim. There is not sufficient evidence to show that average in state tuition is more than 9410 6 pts. Ide ntify any Type I or Type II errors. Type 1: Type II: Accept the claim that in state tuition averages 9410 when it in state tuition averages more than 9410
Contingency Table
A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.
Binomial Distribution
Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.
Need help with these parts of this:
- Use the attached Excel table to see the average cost of tuition by s (public four year college) and use the cost of tuition per year for in state students.
- ) USE every THI RD state START I NG WITH MT (MONTANA) since they are in order from low to high so we get a good sample of all 50
- Do not count (skip) US (United States) or delete that row before you sta
Notice that that US average is different -it is $9650. So our claim is that the average in-state tuition is more than $9410.
You should have 16 states for public four year colleges in-state tuition.
Name of State |
Cost of' Tuition (per year for in s1 |
MT |
6410 |
NV |
6910 |
NC |
7200 |
NY |
7710 |
OK |
8030 |
IA |
8270 |
LA |
8900 |
IN |
9200 |
MD |
9370 |
ME |
9690 |
AL |
10040 |
HI |
10670 |
RI |
11410 |
SC |
12190 |
Ml |
12460 |
PA |
13880 |
- Form the hypotheses (null and alternative) and identify the claim
Claim: Average in-state tuition is more than 9410.
Ho:
HO: μ =9410
Hα:
HA: μ>9410
- State the distribution and test statistic to be used.
- 4pts. Find the sample mean to the nearest whole number.
9521
- 4 pts. Find the sample standard deviation to the nearest who le number.
2151
- Find the value of the test statistic. To 3 decimal places
0.206
- Compute and interpret the p-value. To 2 decimal places
0.42
- Use the previous informat ion to sketch a picture of this situation. CLEARLY, label and sca le the horizonta l ax is and shade the region(s) corresponding to the p-value.
- 6pts. Make the decision to reject or to not reject the null hypothesis. Explain.
Since P value is > 0.05 it is not significant, so do not reject the null hypothesis.
- 6pts. Form a conclusion written in terms of the original claim.
There is not sufficient evidence to show that average in state tuition is more than 9410
- 6 pts. Ide ntify any Type I or Type II errors.
Type 1:
Type II: Accept the claim that in state tuition averages 9410 when it in state tuition averages more than 9410
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