Use the ANOVA summary table to complete parts (a) through (c) below. Source Degrees of Freedom Sum of Squares Mean Square (Variance) F 50 10 в 150 30 AB 25 375 15 3 Error 108 540 Total 143 1,115 a. At the 0.05 level of significance, is there an effect due to factor A? Determine the hypotheses. Choose the correct answer below. A. Ho: There is no effect due to factor A. H,: There is an effect due to factor A. O B. Ho: There is an effect due to factor A.

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At the 0.05 level of​ significance, is there an effect due to factor​ A?

A)Find the​ p-value.

B) What is the conclusion?

Use the ANOVA summary table to complete parts (a) through (c) below.
Source
Degrees of Freedom
Sum of Squares
Mean Square (Variance)
F
50
10
2
B
150
30
6
AB
25
375
15
3
Error
Total
108
540
143
1,115
a. At the 0.05 level of significance, is there an effect due to factor A?
Determine the hypotheses. Choose the correct answer below.
A. Ho: There is no effect due to factor A.
H,: There is an effect due to factor A.
O B. Ho: There is an effect due to factor A.
H: There is no effect due to factor A
Transcribed Image Text:Use the ANOVA summary table to complete parts (a) through (c) below. Source Degrees of Freedom Sum of Squares Mean Square (Variance) F 50 10 2 B 150 30 6 AB 25 375 15 3 Error Total 108 540 143 1,115 a. At the 0.05 level of significance, is there an effect due to factor A? Determine the hypotheses. Choose the correct answer below. A. Ho: There is no effect due to factor A. H,: There is an effect due to factor A. O B. Ho: There is an effect due to factor A. H: There is no effect due to factor A
Expert Solution
Step 1

Significance level = 0.05

F value = 2

Degree of freedom (A) = 5

Degree of freedom (Error) = 108

 

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