Use the accompanying frequency distribution, which shows the number of voting-age citizens in a certain country (in millions) by age, to find the probability that a voting-age citizen chosen at random is in the age range 45 to 64 years old. E Click the icon to view the frequency distribution. The probability is (Round to three decimal places as needed) - X O Frequency Distribution Frequency, f (in millions) Ages 18 to 29 44.2 30 to 44 54.2 45 to 64 65 and over 70.6 45.8 Print Done

Use the accompanying frequency distribution, which shows the number of voting-age citizens in a certain country (in millions) by age, to find the probability that a voting-age citizen chosen at random is in the age range 45 to 64 years old. E Click the icon to view the frequency distribution. The probability is (Round to three decimal places as needed) - X O Frequency Distribution Frequency, f (in millions) Ages 18 to 29 44.2 30 to 44 54.2 45 to 64 65 and over 70.6 45.8 Print Done

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Description: Use the accompanying frequency distribution, which shows the number of voting-age citizens in a certain country (in millions) by age, to find the probability that a voting-age citizen chosen at random is in the age range 45 to 64years old.E Click th

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use the data in the following table, which lists survey results from undergraduate school students. Assume that subjects are randomly selected from those included in the table. If one of the students is randomly selected, find the probability that the selected student took online courses and took in-person courses. Round three decimal places. Student Took Online Courses Yes Student took in-person courses 2800 Student have not taken in- 4460 person courses 0.748 354 0.345 O 285 No 720 140
only HANDWRITTEN answer needed ( NOT TYPED)
A marketing company has randomly surveyed 204 men who watch professional sports. The men were separated according to their educational level (college degree or not) and whether they preferred the NBA or the National Football League (NFL). The results of the survey are shown to the right. Complete parts a through d. Sports Preference NBA College Degree 36 No College O Degree 58 NFL 19 91 a. What is the probability that a randomly selected survey participant prefers the NFL? (Round to four decimal places as needed.) b. What is the probability that a randomly selected survey participant has a college degree and prefers the NBA? (Round to four decimal places as needed.) c. Suppose a survey participant is randomly selected and you are told that he has a college degree. What is the probability that this man prefers the NFL? (Round to four decimal places as needed.) d. Is a survey participant's preference for the NBA independent of having a college degree? No. The two events are not…
Find the indicated probability and interpret the result. From 1975 through 2020, the mean annual gain of the Dow Jones Industrial Average was 653. A random sample of 34 years is selected from this population. What is the probability that the mean gain for the sample was between 400 and 800? Assume o = 1540. The probability is (Round to four decimal places as needed.) Interpret the result. Select the correct choice and fill in the answer box to complete your choice. (Round to two decimal places as needed.) O A. About OB. About OC. About OD. About % of samples of 46 years will have an annual mean gain between 400 and 800. % of samples of 34 years will have an annual mean gain between 653 and 800. % of samples of 34 years will have an annual mean gain between 400 and 800. % of sampl of 34 years will have an annual mean gain between 400 and 653.
Make a Normal Probability Plot for age with TI-84 calculator and show screenshots of calculator
The table summarizes results from 975 pedestrian deaths that were caused by automobile accidents. DriverIntoxicated? Pedestrian Intoxicated? Yes No Yes 45 74 No 285 571 If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was intoxicated or the driver was not intoxicated.Report the answer as a percent rounded to one decimal place accuracy.
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The table summarizes results from 976 pedestrian deaths that were caused by automobile accidents. Driver Intoxicated? Yes No Pedestrian Intoxicated? Yes No 48 83 284 561 If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was not intoxicated. Report the answer as a percent rounded to one decimal place accuracy. You need not enter the "%" symbol. prob = %
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