Use the 0.5 level of significance. Solve for the appropriate test statistic A supervisor is asked to score two groups of employees on how difficult he thinks their job is tocompare if there is a need to restructure the company workload. CV= 2.1792.JobJobDifficultyDifficulty#1#23119.101017215131524716 (0 – E)²E(x – x)²ΣΟx² =s' =Eп — 1X, - X,n,(n, +1).U, = n,n, +2Vn, -1' n, -1n, (п, +1)U, = n,n, +EDt =μΣ D2_(Σ D)2n-1SourceSdfMSFBetween Groupsng-1SsB/dfBmsB/msw(B)= asss$w = Ex-x)²Within Groups (W)N-ngsSw/dfwTotal (T)SSg+ SSwN-1SourcedfMSFEc² G²sscBetween Conditions (C)с-1ssc/dfc msc/msRSCSG²Between Subjects (S)SSs =s-1CSResidual (R)SSR = SST-SSc-sSs(c-1)(s-1)sSR/dfRG²SS7 = EX²Total (T)cs-1CS

Answered: Use the 0.5 level of significance.…

Math

Statistics

Use the 0.5 level of significance. Solve for the appropriate test statistic

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Concept explainers

Confidence Intervals

When we calculate intervals in probability and statistics, it can be simply termed as finding out a confidence interval. The confidence interval is usually calculated from the data set which is observed. The value of the parameter that needs to be calculated is present here only.

Question

Use the 0.5 level of significance. Solve for the appropriate test statistic

A supervisor is asked to score two groups of employees on how difficult he thinks their job is to
compare if there is a need to restructure the company workload. CV= 2.179
2.
Job
Job
Difficulty
Difficulty
#1
#2
3
11
9.
10
10
17
2
15
13
15
2
4
7
16

(0 – E)²
E(x – x)²
ΣΟ
x² =
s' =
E
п — 1
X, - X,
n,(n, +1).
U, = n,n, +
2
Vn, -1' n, -1
n, (п, +1)
U, = n,n, +
ED
t =
μΣ D2_(Σ D)2
n-1
Source
S
df
MS
F
Between Groups
ng-1
SsB/dfB
msB/msw
(B)
= ass
s$w = Ex-x)²
Within Groups (W)
N-ng
sSw/dfw
Total (T)
SSg+ SSw
N-1
Source
df
MS
F
Ec² G²
ssc
Between Conditions (C)
с-1
ssc/dfc msc/msR
S
CS
G²
Between Subjects (S)
SSs =
s-1
CS
Residual (R)
SSR = SST-SSc-sSs
(c-1)(s-1)
sSR/dfR
G²
SS7 = EX²
Total (T)
cs-1
CS

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