Use technology to help you test the claim about the population mean, μ, at the given level of significance,given sample statistics. Assume the population is normally distributed.Claim: μ> 1180; a=0.02;=213.86. Sample statistics: x= 1200.81, n = 250Identify the null and alternative hypotheses. Choose the correct answer below.OA. Ho: > 1180OB. Ho: 21200.81Ha: HS1180Ha: <1200.81OC. Ho: ≤1180H₂: 1180O E. Ho: ≤ 1200.81H₂>1200.81Calculate the standardized test statistic.The standardized test statistic is.(Round to two decimal places as needed.).Determine the P-value.P= (Round to three decimal places as needed.)Determine the outcome and conclusion of the test.Ho. At the 2% significance level, thereO D. Ho: μ>1200.81Ha: μ≤ 1200.81OF. Ho: 21180H₂H1180enough evidence tothe claim.using the

Given that Claim:μ>1180, α=0.02, σ=213.86, Sample statistics: x¯=1200.81, n=250.

Answered: Use technology to help you test the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Answer (4,5,6) with complete solutions
Find the standardized test statistic t for a sample with n = 15, x 10.4, s = 0.8, and a=0.05 if Hg u s101. Round your answer to three decimal %3D %3D places. 1.728 O1312 O 1452 1.631 K
Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…
Test the claim about the population mean, µ, at the given level of significance using the given sample statistics. Claim: p= 30; a=0.06; o= 3.25. Sample statistics: x= 28.9, n= 73 %3D OF Ho H= 30 H3 p 30 Calculate the standardized test statistic. The standardized test statistic is -2.89 (Round to two decimal places as needed.) Determine the critical value(s). Select the correct choice below and fill in the answer box to complete your choice. (Round to two decimal places as needed.) O A. The critical values are t O B. The critical value is
Approximately 58% of all people are able to wink with both eyes. Is this percent different for people who wear glasses? A researcher tests 319 people who wear glasses and found that 204 could wink with both eyes. What can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer z-test for the difference between two population proportions t-test for a population mean z-test for a population proportion t-test for the difference between two dependent population means t-test for the difference between two independent population means The null and alternative hypotheses would be: H0:H0: Select an answer μd p1 p μ1 μ Select an answer ≥ = ≠ ≤ H1:H1: Select an answer μ μ1 p p1 μd Select an answer < ≠ > = The test statistic ? z t = (round to 3 decimal places) The p-value = (round to 4 decimal places) The p-value is ? > ≤ αα. Based on this, we should Select an answer accept reject fail to reject the null hypothesis. Explain…
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Use technology to help you test the claim about the population mean, μ, at the given level of significance, α, using the given sample statistics. Assume the population is normally distributed. Claim: μ>1230; α=0.07; σ=205.81. Sample statistics: x=1263.09, n=250 Calculate the standardized test statistic. The standardized test statistic is enter your response here . (Round to two decimal places as needed.)
Use technology and a t-test to test the claim about the population mean u at the given level of significance a us normally distributed. Claim: u>70; a = 0.10 Sample statistics: x= 70.9, s = 2.8, n= 25 What are the null and alternative hypotheses? Choose the correct answer below. O A. H, µ= 70 HA µZ 70 O B. H, µ2 70 HA µ 70 What is the value of the standardized test statistic? The standardized test statistic is (Round to two decimal places as needed.)
Please help with part e
Use technology to help you test the claim about the population mean, µ, at the given level of significance, a, using the given sample statistics. Assume the population i normally distributed. Claim: µs 1260; a = 0.07; 6 = 206.13. Sample statistics: x= 1282.49, n= 275 Identify the null and alternative hypotheses. Choose the correct answer below. Ο Β. Ho : με 1282.49 Ο Α. Ho μ> 1282.49 H3: us 1282.49 H3: u> 1282.49 O C. H : μ2 1282.49 O D. Hp: µs 1260 Ha:u 1260 Ο Ε. Hρ: μ2 1260 OF. Ho: µ> 1260 Ha: µ< 1260 H3: us 1260 Calculate the standardized test statistic. The standardized test statistic is. (Round to two decimal places as needed.) Determine the P-value. P= (Round to three decimal places as needed )
Use technology to help you test the claim about the population mean, μ, at the given level of significance, a, using the given sample statistics. Assume the population is normally distributed. Claim: μ> 1170; x = 0.08; a=207.79. Sample statistics: x= 1198.51, n = 250 Identify the null and alternative hypotheses. Choose the correct answer below. B. Ho: ≤1198.51 OA. Ho: 21170 Ha: 1170 Ha: 1198.51 OC. Ho: 21198.51 Ha: 1198.51 OE. Ho: 1198.51 Ha: s1198.51 Calculate the standardized test statistic. The standardized test statistic is 2.17. (Round to two decimal places as needed.). Determine the P-value. P=0.015 (Round to three decimal places as needed.) Determine the outcome and conclusion of the test. O D. Ho: H> 1170 Ha: ps 1170 OF. Ho: HS1170 H₂H1170 Reject Ho. At the 8% significance level, there IS enough evidence to support the claim. Time Remaining: 01:29:26

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