Use substitution and partial fractions to find the indefinite integral. √T dx. x-36 Select one: a. O b. O c. √√√x dx = √x + 1n| 6 - √x | − 410g| √x − 6 | + C X- - 36 O e. √ √ √ ³56 dx = 2√x + 6²1 | √x = 6 | + C x-36 √√x x-36 ○ d. _√x dx = 2√x + x² + 61n] √x − 6 | − 61n| √x + 6 | x-36 √x x-36 dx = 61n| 6 - √Ñ |- 61n| 6- √x | + C S dx = 2√x + 1n|6-√x + c |
Use substitution and partial fractions to find the indefinite integral. √T dx. x-36 Select one: a. O b. O c. √√√x dx = √x + 1n| 6 - √x | − 410g| √x − 6 | + C X- - 36 O e. √ √ √ ³56 dx = 2√x + 6²1 | √x = 6 | + C x-36 √√x x-36 ○ d. _√x dx = 2√x + x² + 61n] √x − 6 | − 61n| √x + 6 | x-36 √x x-36 dx = 61n| 6 - √Ñ |- 61n| 6- √x | + C S dx = 2√x + 1n|6-√x + c |
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
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![Use substitution and partial fractions to find the indefinite integral.
dx.
x-36
Select one:
a.
O b.
O c.
O d.
e.
√√√x dx = √x + 1n| 6 - √x | - 410g| √F −6|+C
x-36
x-36
x-36
√ __√x___ dx = 2√x + x² + 61n] √x − 6 | − 6¹n| √x + 6 |
x-36
S__√x
dx = 2√x + 6² | √x + 6 + C
√x+6
dx = 61n 6-√x - 6in 6-√√x+c
x-36
dx = 2√x + ¹n] 6 − √x | +C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa89fcfbc-9661-4037-a401-8de41697cbc3%2Ffec93f3d-0471-45ce-8a19-70196026d1ed%2Fpypqqph_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Use substitution and partial fractions to find the indefinite integral.
dx.
x-36
Select one:
a.
O b.
O c.
O d.
e.
√√√x dx = √x + 1n| 6 - √x | - 410g| √F −6|+C
x-36
x-36
x-36
√ __√x___ dx = 2√x + x² + 61n] √x − 6 | − 6¹n| √x + 6 |
x-36
S__√x
dx = 2√x + 6² | √x + 6 + C
√x+6
dx = 61n 6-√x - 6in 6-√√x+c
x-36
dx = 2√x + ¹n] 6 − √x | +C
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