Use substitution and partial fractions to find the indefinite integral. √T dx. x-36 Select one: a. O b. O c. √√√x dx = √x + 1n| 6 - √x | − 410g| √x − 6 | + C X- - 36 O e. √ √ √ ³56 dx = 2√x + 6²1 | √x = 6 | + C x-36 √√x x-36 ○ d. _√x dx = 2√x + x² + 61n] √x − 6 | − 61n| √x + 6 | x-36 √x x-36 dx = 61n| 6 - √Ñ |- 61n| 6- √x | + C S dx = 2√x + 1n|6-√x + c |

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