USE SALT (a) (c)= 0.9857 2.189 (b) P(0 ≤Z≤ c) = 0.3133 0.89 (c) P(C≤ Z) = 0.1335 1.11

Q: (3) Let X € D4 such that X ‡ R270- Find all Y € D4 such that XY2 = R90. Explain your reasoning.

A: Given:  X, and Y are the elements of the dihedral group D4 such that X≠R270 and XY2=R90. To Find :…

Q: Determine the value of C P(-1.05 ≤ Z≤ 0) = 0.8392 PO

A:

Q: Calculate P (-0.1 < Z < 0.1). (Round to the hundredths).

A:

Q: Find P(-1.40 < Z < 0)     .4192     .1259     .4357     .8907

A: Solution: Let Z be the standard normal random variable with mean μ=0 and standard deviation σ=1…

Q: C= {z | z≥4} D={z|z<7}

A:

Q: Find P(-1.18 < z < 1.18).

A: From the provided information, P (-1.18 &lt; z &lt; 1.18)

Q: find P(-1.2<Z<1.9)

A:

Q: Calculate the following value of P(64≤ x ≤67) f(x) 62 82

A: X is uniformly distributed between 62 and 82 .

Q: P(1.15 < Z < 2.77) =

A: X~N( 0 , 1 )   μ=0 , ?=1 (for standard normal distribution)   Z-score =( x - μ )/?

Q: If P(T>2.66)=0.06 and P(T<−2.66)=0.06​, obtain P(−2.66≤T≤2.66).

A: Given Information: P(T&gt;2.66)=0.06 P(T&lt;−2.66)=0.06​, To obtain P(−2.66≤T≤2.66):…

Q: Calculate P(z<-1.2)

A: The z-score is standard normal variable with mean 0 and standard deviation 1.

Q: P(0.51 ≤ Z ≤ 1.4) =

A: Draw the normal curve and shade the area between z=0.51 and z=1.4.

Q: city law-enforcement official has stated that 20% of the items sold by pawn shops within the city…

A: Since you have posted a question with multiple subparts, we will solve the first 3 sub-parts for…

Q: a. P(Z > 0.74)   b. P(Z ≤ −1.92)   c. P(0 ≤ Z ≤ 1.62)   d. P(−0.90 ≤ Z ≤ 2.94)

A: We have to find givan value

Q: (h) P(1.26 ≤ Z ≤ 2.50) (1) P(1.90 ≤ Z) (1) P(|Z| ≤ 2.50)

A: It is given that the standard normal random variable Z with mean 0 and variance 1.   Note: The…

Q: The result for “Smoking makes me look older? Was F(1,517) = 17.02, p <0.001. Using this result,…

A: It is given that F(1,517) = 17.02. That is, the degrees of freedom for between sum of square is 1…

Q: A consultant estimates that the total weekly computer usage by the company employees to be:…

A: Given query is to find the computer usage for first 14 weeks.

Q: P(−0.71 ≤ Z ≤ 1.34) =

A: Draw the normal curve and shade the area between z=-0.71 and z=1.34.

Q: P(- c ≤ Z ≤ c)=0.9399

A: We have given that  P(- c ≤ Z ≤ c)=0.9399 From the given information we have to find the value of c

Q: Suppose P(E) = 0.154, P(F)= 0.215, and P(F N E) = 0.074. What is P(F | E)?

A: We have given that,  P(E) = 0.154, P(F) = 0.215 and  P(E ∩ F) = 0.074 Then,  We will find P(F/E) = ?…

Q: P(Z ≤ 0.77) = [] P(Z > 1.36) = [ P(−0.70 < Z < 2.06) = |

A: Given P(z≤0.77)

Q: p(0.7 <z < 1.31) =

A: Answer - Find P( 0.7 &lt; Z &lt; 1.31)  = ?

Q: what is p(z<?)=0.88

A: