USE SALT (a) (c)= 0.9857 2.189 (b) P(0 ≤Z≤ c) = 0.3133 0.89 (c) P(C≤ Z) = 0.1335 1.11

Q: (3) Let X € D4 such that X ‡ R270- Find all Y € D4 such that XY2 = R90. Explain your reasoning.

A: Given:  X, and Y are the elements of the dihedral group D4 such that X≠R270 and XY2=R90. To Find :…

Q: Determine the value of C P(-1.05 ≤ Z≤ 0) = 0.8392 PO

A:

Q: (g) P(-1.70 sz≤ 2.00) 3 2 (h) P(1.46 ≤ Z ≤ 2.50) (1) P(1.70 s2) (1) P(IZI ≤ 2.50)

A: We will use Excel function to find the required probabilities based on Standard Normal distribution.

Q: f(x)= k(x² + 4), x = 0,1,2,3 Find p (x< 2).

A: Solution: Given : f(x)=k(x2+4),    x=0,1,2,3

Q: You are given: (i) 1 for 0Sx <110. 110-x (ii) 8=0.05 Find 19 A20.

A: Given            μx=1110-x for 0≤x&lt;110    δ=0.05

Q: Calculate P (-0.1 < Z < 0.1). (Round to the hundredths).

A:

Q: Find P(-1.40 < Z < 0)     .4192     .1259     .4357     .8907

A: Solution: Let Z be the standard normal random variable with mean μ=0 and standard deviation σ=1…

Q: C= {z | z≥4} D={z|z<7}

A:

Q: Z is N(0, 1), find values of c P(-0.91 ≤  Z ≤ c) = 0.8124. b. P(-c≤Z ≤ c) = 0.8686

A: Use EXCEL Procedure for finding the critical value of z to the left of its area.   Follow the…

Q: 9/State the Sufficient condition for the best apfraximation ant Prove t

A:

Q: Find P(-1.18 < z < 1.18).

A: From the provided information, P (-1.18 &lt; z &lt; 1.18)

Q: find P(-1.2<Z<1.9)

A:

Q: Calculate the following value of P(64≤ x ≤67) f(x) 62 82

A: X is uniformly distributed between 62 and 82 .

Q: Given below is the joint probability mass function (PM P₂ (3) 0 1 2 0 0.10 0.20 0.06 0.36 P(x) (a)…

A: Solution-: Given the joint probability mass function of X and Y is   X   0 1 2 total Y 0…

Q: P(1.15 < Z < 2.77) =

A: X~N( 0 , 1 )   μ=0 , ?=1 (for standard normal distribution)   Z-score =( x - μ )/?

Q: If P(T>2.66)=0.06 and P(T<−2.66)=0.06​, obtain P(−2.66≤T≤2.66).

A: Given Information: P(T&gt;2.66)=0.06 P(T&lt;−2.66)=0.06​, To obtain P(−2.66≤T≤2.66):…

Q: Calculate P(z<-1.2)

A: The z-score is standard normal variable with mean 0 and standard deviation 1.

Q: P(0.51 ≤ Z ≤ 1.4) =

A: Draw the normal curve and shade the area between z=0.51 and z=1.4.

Q: city law-enforcement official has stated that 20% of the items sold by pawn shops within the city…

A: Since you have posted a question with multiple subparts, we will solve the first 3 sub-parts for…

Q: z −1

A: To find the required area, use the standard normal table. The required probability value is, P(z…

Q: What is the answer given that P(−1.5465 > z > 1.1143)?

A: P(−1.5465 &gt; z &gt; 1.1143)=? P(a&gt;z&gt;b)=P(z&gt;b)+P(z&lt;a)

Q: a. P(Z > 0.74)   b. P(Z ≤ −1.92)   c. P(0 ≤ Z ≤ 1.62)   d. P(−0.90 ≤ Z ≤ 2.94)

A: We have to find givan value

Q: (h) P(1.26 ≤ Z ≤ 2.50) (1) P(1.90 ≤ Z) (1) P(|Z| ≤ 2.50)

A: It is given that the standard normal random variable Z with mean 0 and variance 1.   Note: The…

Q: Find P(1.73< Z < 2.16)

A:

Q: The result for “Smoking makes me look older? Was F(1,517) = 17.02, p <0.001. Using this result,…

A: It is given that F(1,517) = 17.02. That is, the degrees of freedom for between sum of square is 1…

Q: A consultant estimates that the total weekly computer usage by the company employees to be:…

A: Given query is to find the computer usage for first 14 weeks.

Q: P(-1.18<z≤ _________ )=0.6327   2. P ( ____ ≤z<0.85)=0.6363

A: we have to find probability for normal distribution.

Q: P(−0.71 ≤ Z ≤ 1.34) =

A: Draw the normal curve and shade the area between z=-0.71 and z=1.34.

Q: &lt;1and &lt; 2 are complementary, m &lt; 1 = 5x + 15 and m &lt;2 = 10x. the measure of &lt; 1 is :…

A: Complementary angles are those angles whose sum is 90°.

Q: Shelly is a talented researcher who has just received a large (two-year) research grant. The…

A: Shelly is a talented researcher who has just received a large (two-year) research grant. The…

Q: Consider throwing a die 5 times. Let X be the number of times the outcome is less than 3. Find P(X =…

A: Let p be the probability of getting number less than 3  Result used:  nCr=n!/(r!(n-r)!)…

Q: P(- c ≤ Z ≤ c)=0.9399

A: We have given that  P(- c ≤ Z ≤ c)=0.9399 From the given information we have to find the value of c

Q: Suppose P(E) = 0.154, P(F)= 0.215, and P(F N E) = 0.074. What is P(F | E)?

A: We have given that,  P(E) = 0.154, P(F) = 0.215 and  P(E ∩ F) = 0.074 Then,  We will find P(F/E) = ?…

Q: P(Z ≤ 0.77) = [] P(Z > 1.36) = [ P(−0.70 < Z < 2.06) = |

A: Given P(z≤0.77)

Q: Find  P( −2.25 < z < 1.65) , use the table as given with question paper.

A:

Q: p(0.7 <z < 1.31) =

A: Answer - Find P( 0.7 &lt; Z &lt; 1.31)  = ?

Q: what is p(z<?)=0.88

A: