Use properties of logarithms with the given approximations to evaluate the exp log 5x 0.699 and log 3x 0.477. Use one or both of these values to evaluat a

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter5: Exponential And Logarithmic Functions
Section5.3: Logarithmic Functions And Their Graphs
Problem 140E
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**Topic: Evaluating Logarithmic Expressions using Approximations**

**Instructions**: Use properties of logarithms with the given approximations to evaluate the expression.

Given approximations:
- \(\log_a 5 \approx 0.699\)
- \(\log_a 3 \approx 0.477\)

**Task**: Use one or both of these values to evaluate \(\log_a 125\).

\[
\log_a 125 = \square
\]

**Notes**: 
To find \(\log_a 125\), recognize that 125 can be expressed as \(5^3\). Therefore, using logarithmic properties:

\[
\log_a 125 = \log_a (5^3) = 3 \cdot \log_a 5
\]

Substitute the known value for \(\log_a 5\) into the equation to find the answer.
Transcribed Image Text:**Topic: Evaluating Logarithmic Expressions using Approximations** **Instructions**: Use properties of logarithms with the given approximations to evaluate the expression. Given approximations: - \(\log_a 5 \approx 0.699\) - \(\log_a 3 \approx 0.477\) **Task**: Use one or both of these values to evaluate \(\log_a 125\). \[ \log_a 125 = \square \] **Notes**: To find \(\log_a 125\), recognize that 125 can be expressed as \(5^3\). Therefore, using logarithmic properties: \[ \log_a 125 = \log_a (5^3) = 3 \cdot \log_a 5 \] Substitute the known value for \(\log_a 5\) into the equation to find the answer.
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