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Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. G(X) -12 cos(3t) dt G'(x) = cos(3x) xi Use part one of the fundamental theorem of calculus to find the derivative of the function. g(s) = S · √g³ (t − 1332 dt 18 - g'(s) = 6s5 4s3 ×

Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. G(X) -12 cos(3t) dt G'(x) = cos(3x) xi Use part one of the fundamental theorem of calculus to find the derivative of the function. g(s) = S · √g³ (t − 1332 dt 18 - g'(s) = 6s5 4s3 ×

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. G(X) -12 cos(3t) dt G'(x) = cos(3x) xi
Transcribed Image Text:Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. G(X) -12 cos(3t) dt G'(x) = cos(3x) xi
Use part one of the fundamental theorem of calculus to find the derivative of the function. g(s) = S · √g³ (t − 1332 dt 18 - g'(s) = 6s5 4s3 ×
Transcribed Image Text:Use part one of the fundamental theorem of calculus to find the derivative of the function. g(s) = S · √g³ (t − 1332 dt 18 - g'(s) = 6s5 4s3 ×
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