Use one of the formulas in the table above to integrate dx x8 + 16 (By the way, you're going to need to do a substitution first to be able to use one of the formulas above.) a) First, what substitution do you need to make in the integral to be able to use one of the formulas abov U=

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Chapter1: Functions And Models
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68.
·[√₁² + u²³
· u² du = ²/2 √a² + u² + ½ ln (u + √a² + u²) + C
69.
u² √a² + u² du = ²(a² + 2u²) √a² + u² − ªln (u + √a²+u²) + C
-
a² + u²
a+v
a²+u²
70.
du = √a² + u²
- a ln
In |
+C
u
u
√a²+u²
√a²+u²
71.
du =
+ In (u + √a² + u²) + C
4²
U
du
72.
= In (u + √a² + u²) + С
√a² + u²
u² du
73.
= ²/ (√a² + u²) − ª²ª ln (u + √a² + u²³) + C
a² + u²
du
a²+u²+a
= = 41 | | 4 C
In
+C
Uu
w√a² + u²
du
a²+u²
75.
+C
ủ vả trẻ
a²u
du
U
76.
+C
a²a²+u²
(a² + u²)³/2
Use one of the formulas in the table above to integrate
S
-d.x
√x8 + 16
(By the way, you're going to need to do a substitution first to be able to use one of the formulas above.)
a) First, what substitution do you need to make in the integral to be able to use one of the formulas above?
U =
74.
13
S
·S.
S
Transcribed Image Text:68. ·[√₁² + u²³ · u² du = ²/2 √a² + u² + ½ ln (u + √a² + u²) + C 69. u² √a² + u² du = ²(a² + 2u²) √a² + u² − ªln (u + √a²+u²) + C - a² + u² a+v a²+u² 70. du = √a² + u² - a ln In | +C u u √a²+u² √a²+u² 71. du = + In (u + √a² + u²) + C 4² U du 72. = In (u + √a² + u²) + С √a² + u² u² du 73. = ²/ (√a² + u²) − ª²ª ln (u + √a² + u²³) + C a² + u² du a²+u²+a = = 41 | | 4 C In +C Uu w√a² + u² du a²+u² 75. +C ủ vả trẻ a²u du U 76. +C a²a²+u² (a² + u²)³/2 Use one of the formulas in the table above to integrate S -d.x √x8 + 16 (By the way, you're going to need to do a substitution first to be able to use one of the formulas above.) a) First, what substitution do you need to make in the integral to be able to use one of the formulas above? U = 74. 13 S ·S. S
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