Use Newton's method to approximate a root of the equation cos( s(x² + 3) = x³ as follows. Let x₁ = 2 be the initial approximation. The second approximation is

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Chapter2: Second-order Linear Odes
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**Newton's Method for Approximating Roots**

To approximate a root of the equation \(\cos(x^2 + 3) = x^3\) using Newton's method, follow these steps:

1. **Initial Approximation**: Start with an initial approximation \(x_1 = 2\).

2. **Second Approximation**: We aim to find the second approximation \(x_2\).

In Newton's method, each approximation is refined by using the formula:

\[ x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)} \]

where \(f(x)\) is the function for which we are trying to find the root, and \(f'(x)\) is its derivative.

### Example Calculation (Hypothetical):
For the given function, solve for \(x_2\) using the formula with the initial value \(x_1 = 2\).

**Note:** Further details and the derivative evaluation should be calculated to obtain \(x_2\), helping to refine the approximation iteratively.
Transcribed Image Text:**Newton's Method for Approximating Roots** To approximate a root of the equation \(\cos(x^2 + 3) = x^3\) using Newton's method, follow these steps: 1. **Initial Approximation**: Start with an initial approximation \(x_1 = 2\). 2. **Second Approximation**: We aim to find the second approximation \(x_2\). In Newton's method, each approximation is refined by using the formula: \[ x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)} \] where \(f(x)\) is the function for which we are trying to find the root, and \(f'(x)\) is its derivative. ### Example Calculation (Hypothetical): For the given function, solve for \(x_2\) using the formula with the initial value \(x_1 = 2\). **Note:** Further details and the derivative evaluation should be calculated to obtain \(x_2\), helping to refine the approximation iteratively.
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