Use Newton Raphson method to approximate the root of the function: f(x)= x3 - 2x -3 at xo = 1 What is the approximated root after the 3rd iteration? O 2.058990 O 2.534423 O 1.893289 O 1.893441

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Q: Use Secant method to approximate the root of the function f(x)= x3 - 2x - 3 at xo = 1, x1 = 2 What…

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Q: The following function: f(x)= (0.1x² - 5)(e-0.05x2 + 0.1) has a root at x = ... O a. 6.3246 O b.…

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A: What is the approximated root after the 2nd iteration? 2.2308

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A: Answer: y(0.4)=0.824 after one iteration and y(0.4)=0.69488 after two iterations.

Q: xplain how the Newton-Raphson Method locates the root of a functio

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