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Use mesh analysis to determine ij, iz, and iz in Fig. 3.25.

Use mesh analysis to determine ij, iz, and iz in Fig. 3.25.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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A Fundamentals_of_Electric_Circuits_6th_Ed.pdf - Adobe Reader File Edit View Window Help 148% -E E From Eqs. (3.7.1) to (3.7.4), Оpen 98 (121 of 991) Tools Fill & Sign Comment i = -7.5 A, iz = -2.5 A, iz = 3.93 A, i4 = 2.143 A Practice Problem 3.7 Use mesh analysis to determine i¡, iz, and iz in Fig. 3.25. Answer: i = 12.379 A, iz = 378.9 mA, iz = 3.284 A. 5Ω 24 V 10 Ω 4 A 20 Ω İ Nodal and Mesh Analyses by Inspection 3.6 Figure 3.25 This section presents a generalized procedure for nodal or mesh analysis. It is a shortcut approach based on mere inspection of a circuit. When all sources in a circuit are independent current sources, we do not need to apply KCL to each node to obtain the node-v equations as we did in Section 3.2. mere inspection of the circuit. As an e xample, let us ree xamine the circuit in Fig. 3.2, shown again in Fig. 3.26(a) for convenience. The circuit has two nonreference nodes and the node equations were de- For Practice Prob. 3.7. oltage We can obtain the equations by G2 V1 7.99 x 10.24 in V2 ww
Transcribed Image Text:A Fundamentals_of_Electric_Circuits_6th_Ed.pdf - Adobe Reader File Edit View Window Help 148% -E E From Eqs. (3.7.1) to (3.7.4), Оpen 98 (121 of 991) Tools Fill & Sign Comment i = -7.5 A, iz = -2.5 A, iz = 3.93 A, i4 = 2.143 A Practice Problem 3.7 Use mesh analysis to determine i¡, iz, and iz in Fig. 3.25. Answer: i = 12.379 A, iz = 378.9 mA, iz = 3.284 A. 5Ω 24 V 10 Ω 4 A 20 Ω İ Nodal and Mesh Analyses by Inspection 3.6 Figure 3.25 This section presents a generalized procedure for nodal or mesh analysis. It is a shortcut approach based on mere inspection of a circuit. When all sources in a circuit are independent current sources, we do not need to apply KCL to each node to obtain the node-v equations as we did in Section 3.2. mere inspection of the circuit. As an e xample, let us ree xamine the circuit in Fig. 3.2, shown again in Fig. 3.26(a) for convenience. The circuit has two nonreference nodes and the node equations were de- For Practice Prob. 3.7. oltage We can obtain the equations by G2 V1 7.99 x 10.24 in V2 ww
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