Use LRFD method to find maximum distributed live load (W₂) that can be applied on the concrete slab shown. The details of steel columns and concrete slab are shown in figure. The concrete slab carried (Wo excluding slab self-weight = 20 psf). Weld connection is used in built up section Assume KL=8ft. A992 steel is used. Slab thickness=8in. Concrete weighs 150 16/ft³ 10ft + -100- W₁ = 20 psf W₁= ? + Built up steel column -2.5ft--2.5-2.5f-2.5ft- 2.5ft 2.5ft 2.50 2.5ft + Built up steel column 4L6*6*1

Use LRFD method to find maximum distributed live load (W₂) that can be applied on the concrete slab shown. The details of steel columns and concrete slab are shown in figure. The concrete slab carried (Wo excluding slab self-weight = 20 psf). Weld connection is used in built up section Assume KL=8ft. A992 steel is used. Slab thickness=8in. Concrete weighs 150 16/ft³ 10ft + -100- W₁ = 20 psf W₁= ? + Built up steel column -2.5ft--2.5-2.5f-2.5ft- 2.5ft 2.5ft 2.50 2.5ft + Built up steel column 4L661

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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