Use integration, the Direct Comparison Test, or the Limit Comparison Test to test the integral for convergence. If more. than one method applies, use whatever method you prefer. 00 S Select the correct choice below and, if necessary, fill in the answer box(es) within your choice. 1 O B. dx x +6 The comparison function g(x)= can be used with a comparison test to determine convergence, but since 3 OA. 00 S 0 √x +6 √√x +6 this choice of g(x) is discontinuous at x = OF dx 00 S dx √√x +6 and g(x) are both continuous and positive over the interval. f(x) > g(x) over this interval, and the integral of g(x) over this interval diverges. (Type your answer in interval notation.) 1 this choice of g(x) is discontinuous at x = dx √x+6 dx 1 The comparison function g(x)= can be used with a comparison test to determine convergence, but since 00 OD S dx √√x +6 -S. interval converges, and J dx √√x+6 (Type your answer in interval notation.) dx S OC. The integral converges because 1 ndj- dx √x +6 S and g(x) are both continuous and positive over the interval 0 g(x) over this interval, the integral of g(x) 1 dx D must be rewritten as has the exact value dx By the Direct Comparison Test, the integral converges because f(x) must be rewritten as 1 The comparison function g(x)= can be used with a comparison test to determine convergence, but since x² Ĵ is not defined. must be rewritten as has a finite value. dx D x+6 must be rewritten as dx . By the Limit Comparison Test, the integral diverges because f(x) +6 f(x) and g(x) are both continuous and positive over the interval .0< lim X-9(x) 00, and the integral of g(x) over

Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter39: Symbolism And Algebraic Expressions
Section: Chapter Questions
Problem 5A
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Use integration, the Direct Comparison Test, or the Limit Comparison Test to test the integral for convergence. If more
than one method applies, use whatever method you prefer.
S
dx
O B.
√xº
Select the correct choice below and, if necessary, fill in the answer box(es) within your choice.
The comparison function g(x)= can be used with a comparison test to determine convergence, but since
1
3
x° +6
OA. 00
dx
S
0 √x +6 √√x +6
this choice of g(x) is discontinuous at x =
OF
dx
dx
By the Direct Comparison Test, the integral diverges because f(x)
√√x+6
and g(x) are both continuous and positive over the interval, f(x) > g(x) over this interval, and the integral
of g(x) over this interval diverges.
(Type your answer in interval notation.)
1
this choice of g(x) is discontinuous at x =
dx
dx
izlas
-S.
√√x+6
S
0 √√x +6
1
The comparison function g(x)= can be used with a comparison test to determine convergence, but since
S
interval converges, and J
1
ndj-
dx
√√x+6
(Type your answer in interval notation.)
OC. The integral converges because
dx
dx
By the Limit Comparison Test, the integral converges because f(x)
√x +6
and g(x) are both continuous and positive over the interval,0<lim <oo, the integral of g(x) over this
f(x)
g(x)
0
√√x+6
1
this choice of g(x) is discontinuous at x =
1
dx
OR İZİSİ2
OD.
OE. The integral diverges because J
dx
dx
6
√x +6
has a finite value.
The comparison function g(x)= can be used with a comparison test to determine convergence, but since
3
dx
over this interval converges, and
D
(Type your answer in interval notation.)
Ĵ
D
dx
√x° +6
D
+6
this choice of g(x) is discontinuous at x =
dx
ISAA
-S.
dx
dx
By the Direct Comparison Test, the integral converges because f(x)
+6
√xº +6
and g(x) are both continuous and positive over the interval. f(x) > g(x) over this interval, the integral of g(x)
1
dx
dx
√√x² +6
D
must be rewritten as
has the exact value
dx
must be rewritten as
Ĵ
D
1
The comparison function g(x)=
can be used with a comparison test to determine convergence, but since
x²
must be rewritten as
is not defined.
has a finite value.
dx
√√x° +6
must be rewritten as
By the Limit Comparison Test, the integral diverges because f(x)
f(x)
X-9(x) oo, and the integral of g(x) over
√x+6
√x+6
and g(x) are both continuous and positive over the interval,0<lim
this interval diverges.
(Type your answer in interval notation.)
Transcribed Image Text:Use integration, the Direct Comparison Test, or the Limit Comparison Test to test the integral for convergence. If more than one method applies, use whatever method you prefer. S dx O B. √xº Select the correct choice below and, if necessary, fill in the answer box(es) within your choice. The comparison function g(x)= can be used with a comparison test to determine convergence, but since 1 3 x° +6 OA. 00 dx S 0 √x +6 √√x +6 this choice of g(x) is discontinuous at x = OF dx dx By the Direct Comparison Test, the integral diverges because f(x) √√x+6 and g(x) are both continuous and positive over the interval, f(x) > g(x) over this interval, and the integral of g(x) over this interval diverges. (Type your answer in interval notation.) 1 this choice of g(x) is discontinuous at x = dx dx izlas -S. √√x+6 S 0 √√x +6 1 The comparison function g(x)= can be used with a comparison test to determine convergence, but since S interval converges, and J 1 ndj- dx √√x+6 (Type your answer in interval notation.) OC. The integral converges because dx dx By the Limit Comparison Test, the integral converges because f(x) √x +6 and g(x) are both continuous and positive over the interval,0<lim <oo, the integral of g(x) over this f(x) g(x) 0 √√x+6 1 this choice of g(x) is discontinuous at x = 1 dx OR İZİSİ2 OD. OE. The integral diverges because J dx dx 6 √x +6 has a finite value. The comparison function g(x)= can be used with a comparison test to determine convergence, but since 3 dx over this interval converges, and D (Type your answer in interval notation.) Ĵ D dx √x° +6 D +6 this choice of g(x) is discontinuous at x = dx ISAA -S. dx dx By the Direct Comparison Test, the integral converges because f(x) +6 √xº +6 and g(x) are both continuous and positive over the interval. f(x) > g(x) over this interval, the integral of g(x) 1 dx dx √√x² +6 D must be rewritten as has the exact value dx must be rewritten as Ĵ D 1 The comparison function g(x)= can be used with a comparison test to determine convergence, but since x² must be rewritten as is not defined. has a finite value. dx √√x° +6 must be rewritten as By the Limit Comparison Test, the integral diverges because f(x) f(x) X-9(x) oo, and the integral of g(x) over √x+6 √x+6 and g(x) are both continuous and positive over the interval,0<lim this interval diverges. (Type your answer in interval notation.)
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