Use integration by parts to establish the reduction formula. n ах хе ax dx = n-1 е ахxdx, a #0 a ..... First, select appropriate values for u and dv. u = and dv = dx Now, find du and v. Treat a and n as constants. du = dx and v = Now, make substitutions in the integration by parts formula and simplify. ax dx = dx Finally, apply the constant multiple rule to complete the proof. n ax хе ax dx = dx a x-1eax — 1.ах n - x"-'eax a ах e a n- 1 nx" -'eax
Use integration by parts to establish the reduction formula. n ах хе ax dx = n-1 е ахxdx, a #0 a ..... First, select appropriate values for u and dv. u = and dv = dx Now, find du and v. Treat a and n as constants. du = dx and v = Now, make substitutions in the integration by parts formula and simplify. ax dx = dx Finally, apply the constant multiple rule to complete the proof. n ax хе ax dx = dx a x-1eax — 1.ах n - x"-'eax a ах e a n- 1 nx" -'eax
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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HW # 1

Transcribed Image Text:Use integration by parts to establish the reduction formula.
n
ах
хе
ax dx =
n-1
е ахxdx, a #0
a
.....
First, select appropriate values for u and dv.
u =
and dv =
dx
Now, find du and v. Treat a and n as constants.
du =
dx and v =
Now, make substitutions in the integration by parts formula and simplify.
x" e ax dx = (D - |O dx
Finally, apply the constant multiple rule to complete the proof.
n
ax
хе
ax dx =
dx
a
xn-1eax
n -
x"-'eax
a
ах
e
a
n- 1
nx" -'eax

Transcribed Image Text:Use integration by parts to establish the reduction formula.
ax
хе
n
1
ах
e
е аx dx, a #0
.....
First, select appropriate values for u and dv.
u =
and dv =
dx
Now, find du and v. Treat a and n as constants.
du =
dx and v =
Now, make substitutions in the integration by parts formula and simplify.
O-SO
ax dx =
dx
e
Finally, apply the constant multiple rule to complete the proof.
ax
ax
e
dx
a
n-1
nx'
1
a
ax
e
a
in
a
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